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未处理的异常:FormatException:意外的字符(在字符 1 处) E/flutter ( 6084): <br /> E/flutter ( 6084): ^

php 文件:

$email=$_POST['email'];

    $passworda=$_POST['passworda'];

$sql="SELECT * FROM user WHERE email='".$email."'AND passworda='".$password."' ";
$result=mysqli_query($db,$sql);
$count=mysqli_num_rows($result);
if($count>=1){
echo json_encode("success");
}
else
{
echo json_encode("error");
}

登录页面 Flutter:

class Login extends StatelessWidget {
  TextEditingController email = TextEditingController();
  TextEditingController password = TextEditingController();

  Future login(BuildContext cont) async {
    if (email.text == "" || password.text == "") {
      Fluttertoast.showToast(
        msg: "please complete!",
        toastLength: Toast.LENGTH_SHORT,
        gravity: ToastGravity.CENTER,
        fontSize: 16.0,
      );
    } else {
      var url = "http://192.168.43.150/v1_flutter/lib/php/connection.php";
      var response = await http.post(Uri.parse(url), body: {
        "email": email.text,
        "pass": password.text,
      }, headers: {"Accept":"applicarion/json"});
      var data = jsonDecode(response.body);

      if (data == "success") {
        Navigator.pop(cont);
        Navigator.pushNamed(cont, "/registre");
      } else {
        Fluttertoast.showToast(
          msg: "The user and password does not exist!",
          toastLength: Toast.LENGTH_SHORT,
          gravity: ToastGravity.CENTER,
          fontSize: 16.0,
        );
      }
    }}

控制台:

E/flutter (6084): [错误:flutter/lib/ui/ui_dart_state.cc(198)] 未处理的异常:FormatException:意外的字符(位于 字符 1) E/颤振(6084):

E/颤动​​(6084):^ E/颤振(6084): E/颤振(6084): #0 _ChunkedJsonParser.fail (dart:convert-patch/convert_patch.dart:1383:5) E/颤振(6084): #1 _ChunkedJsonParser.parseNumber (dart:convert-patch/convert_patch.dart:1250:9) E/颤振(6084): #2 _ChunkedJsonParser.parse (dart:convert-patch/convert_patch.dart:915:22) E/颤振(6084): #3 _parseJson (dart:convert-patch/convert_patch.dart:35:10) E/颤振(6084): #4 JsonDecoder.convert (dart:convert/json.dart:612:36) E/颤振(6084): #5 JsonCodec.decode (dart:convert/json.dart:216:41) E/颤振(6084): #6 jsonDecode (dart:convert/json.dart:155:10) E/颤振(6084): #7 Login.login (package:mes_v1/pages/Authentification/login.dart:25:18) E/颤振(6084): E/颤振(6084):

P粉891237912P粉891237912229 天前449

全部回复(1)我来回复

  • P粉244730625

    P粉2447306252024-03-27 00:10:26

    您的代码看起来确实容易出错,但重点关注您的问题:异常看起来很清楚,您的响应解析正在中断。 (我还想说,你应该用 try/catch 包装你的代码,以防止任何代码破坏和正确捕获问题)。

    让我们解决您的问题:

    var data = jsonDecode(response.body);

    这会将您的字符串 (response.body) 转换为 json,这意味着 dataMapList< /code> (其中动态是 Map 或另一个嵌套列表),因此以下内容没有任何意义

    if(数据==“成功”){

    现在,让我们看一下您的 php 代码:

    echo json_encode("成功");

    我不是 php 专家,但从文档来看它应该像下面这样使用:

    $response = array("result" => "Success");
    echo json_encode($response);

    现在让我们回到您的 dart 代码:

    var success = false;
        try{
    
          final baseUrl = "http://192.168.43.150"; // Use final wherever you can
          final url = "$baseUrl/v1_flutter/lib/php/connection.php"; // Improving flexibility
    
          final body = {
            "email": email.text,
            "pass": password.text,
          }; // Decouple in variables for readability
    
          final headers = {"Accept":"application/json"}; // Fix typo
    
          final response = await http.post(Uri.parse(url), body: body, headers: headers);
          final data = jsonDecode(response.body);
          success = data["result"] == "Success";
       } catch(e) {
          print("Catched an error!");
          print(e);
          success = false;
       }
    
       if(success) {
       ...

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