如何显示与 HTML 中具有相同值的 php 行？
从数据库中获取多个具有相同值的数据。我如何构建它将作为子类别工作。如何将所有同名行合并为一个？
该网站应仅显示一个邦板牙。这应该作为一个子类别。
这是此特定页面的代码。
<section class="page-section bg-dark" id="home">
<div class="container">
<h2 class="text-center">Tour Packages</h2>
<div class="d-flex w-100 justify-content-center">
<hr class="border-warning" style="border:3px solid" width="15%">
</div>
<div class="d-flex w-100">
<?php
$packages = $conn->query("SELECT * FROM `packages` order by rand() ");
while($row = $packages->fetch_assoc() ):
$cover='';
if(is_dir(base_app.'uploads/package_'.$row['id'])){
$img = scandir(base_app.'uploads/package_'.$row['id']);
$k = array_search('.',$img);
if($k !== false)
unset($img[$k]);
$k = array_search('..',$img);
if($k !== false)
unset($img[$k]);
$cover = isset($img[2]) ? 'uploads/package_'.$row['id'].'/'.$img[2] : "";
}
$row['description'] = strip_tags(stripslashes(html_entity_decode($row['description'])));
?>
<div class="card w-100 rounded-0">
<img class="card-img-top" src="<?php echo validate_image($cover) ?>" alt="<?php echo $row['title'] ?>" height="200rem" style="object-fit:cover">
<div class="card-body">
<h5 class="card-title truncate-1"><?php echo $row['title'] ?></h5>
<p class="card-text truncate"><?php echo $row['description'] ?></p>
<div class="w-100 d-flex justify-content-end">
<a href="./?page=packages&id=<?php echo md5($row['id']) ?>" class="btn btn-sm btn-flat btn-warning">View Package <i class="fa fa-arrow-right"></i></a>
</div>
</div>
</div>
<?php endwhile; ?>
</div>
<div class="d-flex w-100 justify-content-end">
<a href="./?page=packages" class="btn btn-flat btn-warning mr-4">Explore Package <i class="fa fa-arrow-right"></i></a>
</div>
</div>
</section>