我合并了两个数组(都从不同的mysql表中获取),现在我想将数组中相同值的所有元素求和。
$merged_arr = array_merge($reg, $rel);
Array ( [0] => Array ( [DEPARTMENT] => LEAFSPRINGDIRECT [BASIC INCOME] => 3035.37 [OT PAY] => 0 ) [1] => Array ( [DEPARTMENT] => MUFFLERDIRECT [BASIC INCOME] => 24962.09 [OT PAY] => 5358.76 ) [2] => Array ( [DEPARTMENT] => MUFFLERDIRECT [BASIC INCOME] => 14082.080000000002 [OT PAY] => 3248.4 ) )
这是我尝试过的方法,但是我不得不一遍又一遍地使用if-else语句。
foreach($merged_arr as $key => $val) { // echo $val['BASIC INCOME']."<br>"; // echo array_keys(array_values($new_arr)[$key])[$count]."-".array_values(array_values($new_arr)[$key])[$count]."<br>"; if(array_values(array_values($new_arr)[$key])[$count] == "RADIATORDIRECT") { $new_arr['BASIC INCOME'] += '...'; } $count++; }
我想要的数组应该是这样的:
Array ( [0] => Array ( [DEPARTMENT] => LEAFSPRINGDIRECT [BASIC INCOME] => 3035.37 [OT PAY] => 0 ) [1] => Array ( [DEPARTMENT] => MUFFLERDIRECT [BASIC INCOME] => 39044.17 [OT PAY] => 8607.16 ) )
有什么更简单的方法吗?提前谢谢。
P粉4640820612023-09-11 13:52:23
我会在SQL端这样做:
SELECT DEPARTMENT, SUM(`BASIC INCOME`) AS `BASIC INCOME`, SUM(`OT PAY`) AS `OT PAY` FROM ( SELECT DEPARTMENT, `BASIC INCOME`, `OT PAY` FROM `table_a` -- WHERE ... UNION ALL SELECT DEPARTMENT, `BASIC INCOME`, `OT PAY` FROM `table_b` -- WHERE ... ) UNIONS GROUP BY DEPARTMENT