检索 Router 6 useFetcher 表单中的方法

Question

我别无选择，只能在处理程序中调用获取器的提交方法。它正在访问路由器中正确的操作方法，但是我无法将该方法传递给操作，即表单中定义的 method='POST 。如何访问处理程序内的fetch.Form方法？

const fetcher = useFetcher()

const handlerLogin = useCallback(async () => {
  console.log(fetcher.formMethod) //-> outputting undefined
  fetcher.submit({ value: 'social' }, { method: fetcher.formMethod })
},[])
    
return (
  <Card className={styles.loginCard}>
    <fetcher.Form method='POST' action='/'>
      ..............

Answer 1

尝试这个解决方案，将方法传递给 handlerLogin 函数：

const fetcher = useFetcher();

const handlerLogin = useCallback(async (formMethod) => {
  fetcher.submit({ value: 'social' }, { method: formMethod });
}, []);

return (
  <Card className={styles.loginCard}>
    <fetcher.Form
      method='POST'
      action='/'
    >
      {/* other parts ... */}
      <button onClick={() => handlerLogin(fetcher.formMethod)}>
        Submit
      </button>
    </fetcher.Form>
  </Card>
);