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"SQL查询特定日期范围内有效的记录"

<p>我正在进行出勤控制的工作。签到和签退是表中的两个不同记录</strong></p> <p>有可能有人几天没有签退,但应该算作当天出勤</p> <pre class="brush:php;toolbar:false;">人员ID - 签到时间 - 签退时间 3842 12/17/2022 09:030 -- 从未签退(从12/17.2022之后的每一天都应计算在内) 3843 12/17/2022 08:00 -- 12/17/2022 09:30. (下面是同一天) 3843 12/17/2022 11:00 -- 12/17/2022 13:30. (上面是同一天) 3841 12/17/2022 08:00 -- 12/17/2022 17:45. (简单同一天) 3844 12/17/2022 22:00 -- 12/18/2022 6:40. (跨越午夜-应计算12/17和12/18) 我期望的结果是 12/15 1人 12/17 4人 12/18 2人</pre> <p>我想知道X天有多少人出勤</p> <p>我有点困惑如何处理两个不同的记录(签到和签退)或者只有一个记录可用(签到)</p> <pre class="brush:php;toolbar:false;">CREATE TABLE `my_history` ( `id` int(11) NOT NULL AUTO_INCREMENT, `person_id` int(11) DEFAULT NULL, `action` varchar(24) DEFAULT NULL, `when_created` timestamp NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8;</pre> <p>一些插入语句</p> <pre class="brush:php;toolbar:false;">INSERT INTO `my_history` ( `person_id`, `action`, `when_created`) VALUES ( 3842, 'checked_in', '2022-12-15 08:00:00'), ( 3842, 'checked_out', '2022-12-15 09:30:00'), ( 3842, 'checked_in', '2022-12-17 09:30:00'), ( 3843, 'checked_in', '2022-12-17 08:00:00'), ( 3843, 'checked_out', '2022-12-17 09:30:00'), ( 3843, 'checked_in', '2022-12-17 11:00:00'), ( 3843, 'checked_out', '2022-12-17 13:30:00'), ( 3841, 'checked_in', '2022-12-17 08:00:00'), ( 3841, 'checked_out', '2022-12-17 17:42:00'), ( 3844, 'checked_in', '2022-12-17 22:00:00'), ( 3844, 'checked_out', '2022-12-18 06:40:00'); CREATE TABLE person ( id INT(11) ) INSERT INTO person VALUES (3841), (3842), (3843), (3844)</pre></p>
P粉884667022P粉884667022416 天前571

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  • P粉253800312

    P粉2538003122023-09-01 09:56:28

    通常,要测试这种情况,您需要查看您感兴趣的日期是否大于入住日期并小于退房日期。例如

    WHERE checkin <= '2022-12-14' and
          checkout >= '2022-12-14'

    为了解决退房日期可以为空但仍然“OK”的情况,我们只需用满足条件的值替换空值。

    SELECT *
    FROM my_history
    WHERE checkin <= '2022-12-14' and
          COALESCE(checkout,'2022-12-14') >= '2022-12-14'

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  • P粉317679342

    P粉3176793422023-09-01 09:17:04

    由于要求变更,已删除旧答案。匆忙之中,没有时间解释。

    SELECT
      param.check_date,
      COUNT(DISTINCT p.id)
    FROM
    (
      SELECT timestamp '2022-12-15 00:00'   AS check_date
      UNION ALL
      SELECT timestamp '2022-12-17 00:00'   AS check_date
      UNION ALL
      SELECT timestamp '2022-12-18 00:00'   AS check_date  
    )
      AS param
    CROSS JOIN
      person       AS p
    INNER JOIN
      my_history   AS h
        ON
          h.person_id = p.id
        AND
          h.when_created
          >=
          COALESCE(
            (
              SELECT when_created
                FROM my_history
               WHERE person_id = p.id
                 AND when_created <= check_date
            ORDER BY when_created DESC
               LIMIT 1
            ),
            check_date
          )
        AND
          h.when_created < check_date + INTERVAL 1 DAY
        AND
          h.action = 'checked_in'
    GROUP BY
      param.check_date

    https://dbfiddle.uk/RXx0x9xt

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