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MySQL里求给定的时间是所在月份的第几个礼拜
Share 一个昨天写的函数。 目的是求给定的时间是所在月份的第几个礼拜。
[sql]
DELIMITER $$
USE `t_girl`$$
DROP FUNCTION IF EXISTS `weekofmonth`$$
CREATE DEFINER=`root`@`localhost` FUNCTION `weekofmonth`(
f_datetime DATETIME
) RETURNS INT(11)
BEGIN
-- Created by ytt.
DECLARE v_result INT;
DECLARE v_weekno INT;
SET v_weekno =
CASE DAYOFWEEK(f_datetime)
WHEN 1 THEN 7
WHEN 2 THEN 1
WHEN 3 THEN 2
WHEN 4 THEN 3
WHEN 5 THEN 4
WHEN 6 THEN 5
WHEN 7 THEN 6
END;
SET v_result = CEIL(DAYOFMONTH(DATE_SUB(f_datetime,INTERVAL v_weekno DAY))/7)+1;
RETURN v_result;
END$$
DELIMITER ;
演示下结果:
SELECT weekofmonth(NOW()) AS result;
query result:
result
4
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