PHP向脚本提交POST数据_PHP
- WBOY原创
- 2016-06-01 12:34:52965浏览
$name = urlencode($_POST['name'];
$pass = urlencode($_POST['pass'];
$params = "name=$name&pass=$pass";
$length = strlen($params);
$fp = fsockopen("localhost",80,$errno,$errstr,10) or exit($errstr."--->".$errno);
$header = "POST /test/re.php HTTP/1.1\r\n"; ##原来少了个“/”
$header .= "Host:localhost\r\n";
$header .= "Referer:localhost/test/re.php\r\n";
$header .= "Content-Length: ".$lenght."\r\n";
$header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$header .= "Connection: Close\r\n\r\n";
$header .= $params."\r\n"; ##POST方式发送不能接在脚本后面
fputs($fp,$header);
fclose($fp);
声明:本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn