如何使用PHP开发简单的在线考试和成绩查询功能
随着互联网的普及,越来越多的教育机构开始借助网络平台进行在线教育和考试,这为学生和教师提供了便利。为了满足教育机构的需求,本文将介绍如何使用PHP开发一个简单的在线考试和成绩查询功能,并提供具体的代码示例。
<html> <head> <title>在线考试</title> </head> <body> <h1>在线考试</h1> <form action="submit_exam.php" method="post"> <p>问题1: ...</p> <input type="radio" name="answer1" value="A"> A<br> <input type="radio" name="answer1" value="B"> B<br> <input type="radio" name="answer1" value="C"> C<br> <input type="radio" name="answer1" value="D"> D<br><br> <p>问题2: ...</p> <input type="radio" name="answer2" value="A"> A<br> <input type="radio" name="answer2" value="B"> B<br> <input type="radio" name="answer2" value="C"> C<br> <input type="radio" name="answer2" value="D"> D<br><br> ... <input type="submit" value="提交"> </form> </body> </html>
<?php $conn = mysqli_connect("localhost", "root", "", "exam"); // 连接数据库 if ($conn->connect_error) { die("连接失败:".$conn->connect_error); } $answer1 = $_POST['answer1']; $answer2 = $_POST['answer2']; ... $sql = "INSERT INTO students (answer1, answer2, ...) VALUES ('$answer1', '$answer2', ...)"; if ($conn->query($sql) === TRUE) { echo "提交成功"; } else { echo "提交失败:" . $conn->error; } $conn->close(); ?>
<html> <head> <title>成绩查询</title> </head> <body> <h1>成绩查询</h1> <form action="query_score.php" method="post"> <label for="studentID">学生ID:</label> <input type="text" id="studentID" name="studentID"><br><br> <input type="submit" value="查询"> </form> </body> </html>
<?php $conn = mysqli_connect("localhost", "root", "", "exam"); // 连接数据库 if ($conn->connect_error) { die("连接失败:".$conn->connect_error); } $studentID = $_POST['studentID']; $sql = "SELECT * FROM students WHERE studentID = '$studentID'"; $result = $conn->query($sql); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { echo "学生ID: " . $row["studentID"]. " - 学生姓名: " . $row["studentName"]. " - 考试科目: " . $row["subject"]. " - 考试成绩: " . $row["score"]. "<br>"; } } else { echo "该学生不存在"; } $conn->close(); ?>
通过上述步骤,我们就实现了一个简单的在线考试和成绩查询功能。使用PHP编程语言,配合数据库操作,我们可以方便地进行在线考试,并且能够通过学生ID来查询学生的考试成绩。这为教育机构提供了便利,也为学生提供了灵活的学习途径。
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