给定一个矩阵,我们需要打印矩阵的边界元素并显示它们的总和。
参考下面给出的矩阵 -
1 2 3 4 5 6 7 8 9
1 2 3 4 6 7 8 9
边界元素之和:1 + 2 + 3 + 4 + 6 + 7 + 8 + 9 = 40
求边界矩阵之和的逻辑如下如下 -
for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("</p><p>"); }
以下是用于打印矩阵边界元素之和的C程序 -
#include<stdio.h> #include<limits.h> int main(){ int m, n, sum = 0; printf("</p><p>Enter the order of the matrix : "); scanf("%d %d",&m,&n); int i, j; int mat[m][n]; printf("</p><p>Input the matrix elements</p><p>"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++) scanf("%d",&mat[i][j]); } printf("</p><p>Boundary Matrix</p><p>"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("</p><p>"); } printf("</p><p>Sum of boundary is %d", sum); }
当执行上述程序时,会产生以下结果 -
Enter the order of the matrix : 3 3 Input the matrix elements : 1 2 3 4 5 6 7 8 9 Boundary Matrix : 1 2 3 4 6 7 8 9 Sum of boundary is 40
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