C语言公式计算利息金额

问题

编写一个C程序，计算存款金额在一些年后的增加利息

解决方案

计算利息的公式为 −

M=((r/100) * t);
A=P*exp(M);

Where r= rate of interest

            t=no. of years

            P=amount to be deposited

            M=temporary variable

            A= Final amount after interest

算法

START
Step 1: declare double variables
Step 2: read amount to be deposited
Step 3: read rate of interest
Step 4: read years you want to deposit
Step 5: Calculate final amount with interest
         I. M=((r/100) * t);
         II. A=P*exp(M);
Step 6: Print final amount
STOP

示例

#include<stdio.h>
#include<math.h>
#include<ctype.h>
int main(){
   double P,r,t,A,M;
   printf("amount to be deposit in the bank: ");
   scanf("%lf",&P);
   printf("</p><p> enter the rate of interest:");
   scanf("%lf",&r);
   printf("</p><p> How many years you want to deposit:");
   scanf("%lf",&t);
   M=((r/100) * t);
   A=P*exp(M);
   printf("</p><p> amount after %0.1lf years with interest is:%0.2lf",t,A);
   return 0;
}

输出

amount to be deposit in the bank: 50000
enter the rate of interest:6.5
How many years you want to deposit:5
amount after 5.0 years with interest is:69201.53

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