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检查给定字符串是否是关键字的C程序?

王林
王林转载
2023-09-08 14:45:041047浏览

检查给定字符串是否是关键字的C程序?

关键字是在C++库中预定义或保留的单词,具有固定的含义,并用于执行内部操作。C++语言支持超过64个关键字。

每个关键字都以小写字母形式存在,如auto、break、case、const、continue、int等。

C++语言中的32个关键字也可在C语言中使用。

auto double int struct
break else long switch
case enum register typedef
char extern return union
const float short unsigned
continue for signed void
default goto sizeof volatile
do if static while

这是C++中新增的30个保留字,不在C语言中。

asm dynamic_cast namespace reinterpret_cast
bool explicit new static_cast
catch false operator template
class friend private this
const_cast inline public throw
delete mutable protected true
try typeid typename using
using using wchar_t

Input: str=”for”
Output: for is a keyword

Explanation

  • 关键字是程序中不能用作变量名的保留字。

  • C编程语言中有32个关键字。

将字符串与每个关键字进行比较,如果字符串相同,则字符串是关键字。

Example

 示例

#include <stdio.h>
#include <string.h>
int main() {
   char keyword[32][10]={
      "auto","double","int","struct","break","else","long",
      "switch","case","enum","register","typedef","char",
      "extern","return","union","const","float","short",
      "unsigned","continue","for","signed","void","default",
      "goto","sizeof","voltile","do","if","static","while"
   } ;
   char str[]="which";
   int flag=0,i;
   for(i = 0; i < 32; i++) {
      if(strcmp(str,keyword[i])==0) {
         flag=1;
      }
   }
   if(flag==1)
      printf("%s is a keyword",str);
   else
      printf("%s is not a keyword",str);
}

输出

which is a keyword

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