如果在当前事务中间执行 START TRANSACTION,则当前事务将被提交并结束。当前事务中所做的所有数据库更改都将永久生效。这称为 START TRANSACTION 命令的隐式提交。
假设我们在表“marks”中有以下值
mysql> select * from marks; +------+---------+-----------+-------+ | Id | Name | Subject | Marks | +------+---------+-----------+-------+ | 1 | Aarav | Maths | 50 | | 1 | Harshit | Maths | 55 | | 3 | Gaurav | Comp | 69 | +------+---------+-----------+-------+ 3 rows in set (0.00 sec) mysql> START TRANSACTION; Query OK, 0 rows affected (0.00 sec) mysql> INSERT INTO Marks Values(4, 'Rahul','History',40); Query OK, 1 row affected (0.00 sec) mysql> INSERT INTO Marks Values(5, 'Yashraj','English',48); Query OK, 1 row affected (0.00 sec) mysql> START TRANSACTION; Query OK, 0 rows affected (0.00 sec)
在此示例中,我们可以观察到,当在当前事务中间执行 START TRANSACTION 语句时,它将隐式结束当前事务并提交更改。
mysql> select * from marks; +------+---------+-----------+-------+ | Id | Name | Subject | Marks | +------+---------+-----------+-------+ | 1 | Aarav | Maths | 50 | | 1 | Harshit | Maths | 55 | | 3 | Gaurav | Comp | 69 | | 4 | Rahul | History | 40 | | 5 | Yashraj | English | 48 | +------+---------+-----------+-------+ 5 rows in set (0.00 sec)
以上是如果在当前事务的中间执行 START TRANSACTION 命令,当前 MySQL 事务会发生什么?的详细内容。更多信息请关注PHP中文网其他相关文章!