在几何学中,菱形是四个边长相同的四边形。菱形与形状菱形相似。如果菱形的对角线成直角,那么它就变成正方形。
菱形的性质是 -
下图是菱形
给定对角线,假设 d1 和 d2 的任务是找到菱形的面积和周长,其中面积是形状所占据的空间,周长是其边界将覆盖的空间
要计算长方体的面积和周长,有一个公式 -
Input-: d1=6 and d2=12 Output-: The perimeter of rhombus with given diagonals are :26 The area of rhombus with given diagonals are :36
Start Step 1 -> declare function to calculate perimeter of rhombus int perimeter(int d1, int d2) Declare variable long long int perimeter Set perimeter = 2 * sqrt(pow(d1, 2) + pow(d2, 2)) Print perimeter Step 2 -> Declare function to calculate area of rhombus int area(int d1, int d2) Declare long long int area Set area = (d1 * d2) / 2 Print area Step 3 -> In main() Declare variable int d1 = 6, d2 = 12 Call perimeter(d1, d2) Call area(d1, d2) Stop
#include <iostream> #include <math.h> using namespace std; // program to calculate perimeter of rhombus int perimeter(int d1, int d2){ long long int perimeter; perimeter = 2 * sqrt(pow(d1, 2) + pow(d2, 2)); cout<< "The perimeter of rhombus with given diagonals are :"<<perimeter; } //program to calculate area of rhombus int area(int d1, int d2){ long long int area; area = (d1 * d2) / 2; cout<<"</p><p>The area of rhombus with given diagonals are :"<< area; } int main(){ int d1 = 6, d2 = 12; perimeter(d1, d2); area(d1, d2); return 0; }
The perimeter of rhombus with given diagonals are :26 The area of rhombus with given diagonals are :36
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