我们可以使用数组循环来从列表中返回最大的元素。主要是通过比较模型来实现的。在某个列表中,最大的数字将与该列表中的所有元素进行比较。该过程将考虑“n”作为输入数量,并将其作为数据值存储在数组中。之后,程序将在循环结束后在输出控制台上显示最大的元素。
在本文中,我们将帮助您理解并编写一些Java代码,通过这些代码您可以从数组列表中找到最大的元素。
We can find a largest number by sorting an array. To define a void ArrayList and add all elements of array to it. Passing the ArrayList to Collections.max() and the entire process will take a run.
For this operation, you can declare a set of input as a form of array at the beginning. This creates a base to execute a logic. The algorithm uses this loop to find out the particular result (largest number of that loop).
Let's take an example.
arr[]= {1,10,4,15,9,85,63,108}
Output: 108
从数组中找到最大的数,通常会使用两种类型的函数 -
Max () – Use to find the max function from the list
for Loop - Use to perform iteration for every element.
首先,您应该声明一个数组,然后对其进行初始化。对于迭代,我们需要两个循环,然后比较元素以获取最大的数字,数据需要按降序进行交换。
Here is the general algorithm for to find out the largest element in a list by using Java −
第一步 − 开始
第2步 − 初始化arr[]
第三步 − max=arr[0]
第4步 − i=0;i
第四步 - 如果 (arr[i]>max)max=arr[i]
步骤 5(1) − 打印
步骤 5(2) − 打印 MAX
Step 6 − Terminate
有两种方法可以执行该操作。在下面的语法中描述了这两种方法。
coll means; the total collection from which the maximum element will be filtered out.
comp意味着; 可以进行操作的比较器。
public static <T extends an Object & make it Comparable<? super T>> T max(Collection of data <? extends T> coll) or; public static <T> T max(Collection of the data <? extends T> coll, Comparator<? super T> comparator)
Below approaches are useful for finding out the largest value in an array list −
方法一 - 迭代方法
Approach 2 − Int method by Java 8 stream
Approach 3 − max() method
Approach 4 − Using ForEach Loop
Approach 5 − Using Library Function
在这种方法中,时间复杂度是基于给定数据集的大小为0。而且不需要额外的辅助空间。
Recursive way to get max value.
Basic Condition of the method : if , (m==1) value return arr[0]
Else, get return the value of: maximum (arr[n-1], getmax(arr[], n-1))
import java.util.*; public class CollectionsofmaxfileARRDD { public static void main (String[] args) { List<Integer> list = Arrays.asList(2010, 1010, 1001, 1400, 2501); Integer max = Collections.max(list, Collections.reverseOrder()); System.out.println("Output from the particular string: "+max); } }
Output from the particular string: 1001
In this method the time complexity is totally 0 and the auxiliary space has no extra space needed because it is constant.
import java.util.Arrays; public class arbrdd { public static void main (String[] args){ int arr[] = {07, 16, 10, 2001, 1997}; int max = Arrays.stream(arr).max().getAsInt(); System.out.println("Largest array is found from the array list" +max); } }
Largest array is found from the array list2001
通过使用max()方法,我们将使用以下过程构建Java代码 -
声明带有最大值的变量
Initialize with the first element of an array
运行循环
array[a]>maximum, set max = array[a]
打印输出
import java.util.*; public class arbrdd{ public static void main(String[] args){ int arr[] = {10, 07, 16, 2001,1997}; List<Integer> list = new ArrayList<>(); for(int a=0;a<arr.length;a++){ list.add(arr[a]); } System.out.println("Largest array present in the particular array list is " +Collections.max(list)); } }
Largest array present in the particular array list is 2001
通过使用ForEach循环,我们将使用以下过程构建Java代码-
Call recursive say get max
操作的基本条件:if,(a==1) 返回数组[0]
否则,返回max(array[a-1], getmax(array, a-1))
import java.util.Arrays; import java.util.List; public class maxarrayval { public static void main(String[] args){ List<Integer> arrayList = Arrays.asList(10, 07, 16, 2001, 1997, 10052022); int maxValue0710 = Integer.MIN_VALUE; for (Integer integer : arrayList) { if (integer > maxValue0710) maxValue0710 = integer; } System.out.println("The maximum value present in the array is " + maxValue0710); } }
The maximum value present in the array is 10052022
By using the library functions, here we will build a Java code by using the below process −
Maximum(arr,0,end)
从该数组列表中读取倒数第二个元素
Find the larger element between 2nd last and last one from array data
Max value recursive iteration
结束
import java .io.*; import java.util.*; public class ARBRDD{ static int largest(int []arr,int n){ Arrays.sort(arr); return arr[n - 1]; } static public void main (String[] args){ int []arr = {07, 10, 2001,1997, 10052022}; int n = arr.length; System.out.println(largest(arr, n)); } }
10052022
In this article; today we learnt how to get the Largest Element in return from an array List using Java.
通过可能的条件和使用此处提到的逻辑编写的程序,我们如何使用数组循环,并根据所有可能的条件和此处编写的一些代码的处理过程来满足每个理论。
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