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首页  >  文章  >  数据库  >  MySQL派生表联表查询的示例分析

MySQL派生表联表查询的示例分析

PHPz
PHPz转载
2023-04-17 18:40:061230浏览

前情提要：

公司运营的一个商城系统，忽然发现订单提现功能有问题，有大量的商户体现金额和订单金额不一致。于是产生了需求，需要把提现表和供应商表作为一个结果集，连接上订单表中的订单金额，通过计算订单表的金额和体现表商户提现的金额进行比对，查看商户是多提现了还是少提现了。

下面记录我的查询过程。

查询过程：

刚开始，第一步我以提现表为主表，查询出来相关结果。MySQL语句如下

SELECT  count(ysw.supply_id) AS '提现次数',ysw.user_id AS '供应商对应的用户ID', ysw.supply_id  AS '供应商ID' ,SUM(ysw.money)  AS '供应商提现总金额',
case ysw.pay_type when 10 then '微信' when 20 then '支付宝' else '银行卡' end as '支付方式' ,
ys.supply_name AS '供应商名称',ys.money AS '供应商余额',ys.freez_money AS '供应商冻结金额（已提现金额）'
FROM yoshop_supply_withdraw AS ysw LEFT JOIN yoshop_supply AS ys ON ysw.supply_id = ys.supply_id
WHERE ysw.create_time < 1647446400 AND ysw.apply_status IN (10,20,40) GROUP BY ysw.supply_id
ORDER BY SUM(ysw.money) DESC ;

查询结果如图是正常的：

MySQL派生表联表查询的示例分析

接下来，我在左链接上订单表的数据，又添加一个了left join，金额相关数据发生了变化严重不一致,而且查询时间明显延长，MySQL语句如下

SELECT  count(ysw.supply_id) AS &#39;提现次数&#39;,ysw.user_id AS &#39;供应商对应的用户ID&#39;, ysw.supply_id  AS &#39;供应商ID&#39; ,SUM(ysw.money)  AS &#39;供应商提现总金额&#39;,
case ysw.pay_type when 10 then &#39;微信&#39; when 20 then &#39;支付宝&#39; else &#39;银行卡&#39; end as &#39;支付方式&#39; ,
ys.supply_name AS &#39;供应商名称&#39;,ys.money AS &#39;供应商余额&#39;,ys.freez_money AS &#39;供应商冻结金额（已提现金额）&#39;,SUM(yo.pay_price)

FROM yoshop_supply_withdraw AS ysw LEFT JOIN yoshop_supply AS ys ON ysw.supply_id = ys.supply_id
LEFT JOIN yoshop_order AS yo ON yo.supply_ids =ysw.supply_id 

WHERE ysw.create_time < 1647446400 AND ysw.apply_status IN (10,20,40) GROUP BY ysw.supply_id
ORDER BY SUM(ysw.money) DESC ;

查询结果对比图如下：

MySQL派生表联表查询的示例分析

经过实践，我想直接通过左连接查询到提现表金额和订单表金额是行不通的。通过网上查资料，以及在技术群里请教，

优化了思路： 把提现的统计好,把订单的统计好， 最后两个结果集再根据供应商id做个链接

接下来就是，三步走了， 第一步：把提现的统计好，上面第一次尝试的第一步就是了， 第二步：把订单表的数据统计好。由于使用系统的原因，我直接使用的订单商品表计算的订单总金额，这一步也是分三步走的，我直接上代码：

1.查询yoshop_order所有进行中，已完成的 订单id(order_id);
	SELECT order_id FROM yoshop_order WHERE order_status IN (10,30);
	
2.查询没有退款的订单ID
	SELECT order_id FROM yoshop_order WHERE order_status IN (10,30) AND order_id NOT IN ( SELECT order_id FROM yoshop_order_refund);
	
3.查询订单商品表中 所有的订单金额

SELECT  supply_id  AS &#39;供应商ID&#39; , SUM(total_pay_price)  AS &#39;供应商订单总金额&#39; FROM yoshop_order_goods WHERE  create_time < 1647446400 AND order_pay_status = 0  AND  order_id IN(SELECT order_id FROM yoshop_order WHERE order_status IN (10,30) AND order_id NOT IN ( SELECT order_id FROM yoshop_order_refund)	 )  GROUP BY supply_id 
ORDER BY SUM(total_pay_price) DESC ;

接下来就是进行把第一步和第二步的查询结果当作派生表，进行左连接查询。我在这一步耗费的时间和精力最多。如果你能认真看完，相信一定会有收货。我在这里把我错误的过程也进行了记录 第一次错误拼接：

SELECT * FROM  (
	SELECT  count(ysw.supply_id) AS &#39;提现次数&#39;,ysw.user_id AS &#39;供应商对应的用户ID&#39;, ysw.supply_id  AS &#39;supply_id&#39; ,SUM(ysw.money)  AS &#39;供应商提现总金额&#39;,
	case ysw.pay_type when 10 then &#39;微信&#39; when 20 then &#39;支付宝&#39; else &#39;银行卡&#39; end as &#39;支付方式&#39; ,
	ys.supply_name AS &#39;供应商名称&#39;,ys.money AS &#39;供应商余额&#39;,ys.freez_money AS &#39;供应商冻结金额（已提现金额）&#39;
	FROM yoshop_supply_withdraw AS ysw LEFT JOIN yoshop_supply AS ys ON ysw.supply_id = ys.supply_id
	WHERE ysw.create_time < 1647446400 AND ysw.apply_status IN (10,20,40) GROUP BY ysw.supply_id
	ORDER BY SUM(ysw.money) DESC ) AS t1 
union all    // left join ,这里是注释记得删除

SELECT * FROM   --  这里是错误的不应该在查询
		(SELECT  supply_id  AS &#39;supply_id&#39; , SUM(total_pay_price)  AS total_pay_price FROM yoshop_order_goods WHERE  create_time < 1647446400 AND order_pay_status = 0  AND  order_id IN(
	SELECT order_id FROM yoshop_order WHERE order_status IN (10,30) AND order_id NOT IN (
	SELECT order_id FROM yoshop_order_refund)	 )  GROUP BY supply_id 
ORDER BY SUM(total_pay_price) DESC ) AS t2
								
ON t1.suppply_id = t2.suppply_id

通过这一次试错，明显看出我把left join 和 union all 的含义记错了,并且在拼接的时候重复使用了select * from 。虽然是试错了，但也是有收货的，接下来进行了第二次错误的拼接：

SELECT t1.提现次数 ,t1.供应商对应的用户ID ,t1.supply_id, t1.支付方式 ,t1.供应商名称,t1.供应商余额, t1.供应商冻结金额（已提现金额）, t2.total_pay_price FROM  (
SELECT  count(ysw.supply_id) AS &#39;提现次数&#39;,ysw.user_id AS &#39;供应商对应的用户ID&#39;, ysw.supply_id  AS supply_id ,SUM(ysw.money)  AS &#39;供应商提现总金额&#39;,
case ysw.pay_type when 10 then &#39;微信&#39; when 20 then &#39;支付宝&#39; else &#39;银行卡&#39; end as &#39;支付方式&#39; ,
	ys.supply_name AS &#39;供应商名称&#39;,ys.money AS &#39;供应商余额&#39;,ys.freez_money AS &#39;供应商冻结金额（已提现金额）&#39;
	FROM yoshop_supply_withdraw AS ysw LEFT JOIN yoshop_supply AS ys ON ysw.supply_id = ys.supply_id
	WHERE ysw.create_time < 1647446400 AND ysw.apply_status IN (10,20,40) GROUP BY ysw.supply_id
	ORDER BY SUM(ysw.money) DESC ) AS t1 
        
 LEFT JOIN
		
(SELECT  supply_id  AS supply_id , SUM(total_pay_price)  AS total_pay_price FROM 
yoshop_order_goods WHERE  create_time < 1647446400 AND order_pay_status = 0  
AND  order_id IN(
SELECT order_id FROM yoshop_order WHERE order_status IN (10,30) 
AND order_id NOT IN (
SELECT order_id FROM yoshop_order_refund)	 )  
GROUP BY supply_id 
ORDER BY SUM(total_pay_price) DESC ) AS t2						
ON t1.suppply_id = t2.suppply_id

通过这两次错误的尝试，以及根据尝试过程中MySQL给出的错误提示，知道自己是在左连接上使用错误了，应该在开始查询出来所有的字段，left join 后不能在使用select * 最后，回想了一遍自己所学的left join的语法，写出了最后的正确的查询结果

SELECT t1.supply_id &#39;供应商ID&#39;,t1.supply_name &#39;供应商名称&#39;,t1.user_id &#39;供应商绑定的用户ID&#39;,t1.withdrawtime &#39;供应商提现次数&#39; ,t1.supplyallmoney &#39;供应商提现金额&#39;,t1.payway &#39;供应商提现方式&#39;,t1.supply_money &#39;供应商账户余额&#39;,t1.supply_free_money &#39;供应商冻结余额（已提现金额）&#39;,
t2.total_pay_price &#39;供应商订单总金额&#39;,t2.order_id &#39;供应商订单数量&#39;
FROM  (											
SELECT  count(ysw.supply_id) AS withdrawtime,  ysw.user_id AS user_id,   ysw.supply_id  AS supply_id ,  SUM(ysw.money)  AS supplyallmoney,   ysw.alipay_name AS alipay_name ,ysw.alipay_account AS alipay_account,  ysw.audit_time as audit_time ,  ysw.bank_account AS bank_account,   ysw.bank_card AS bank_card,   ysw.bank_name AS bank_name,
case ysw.pay_type when 10 then &#39;微信&#39; when 20 then &#39;支付宝&#39; else &#39;银行卡&#39; end as payway ,
ys.supply_name AS supply_name,  ys.money AS supply_money,  ys.freez_money AS supply_free_money
FROM yoshop_supply_withdraw AS ysw LEFT JOIN yoshop_supply AS ys ON ysw.supply_id = ys.supply_id
WHERE ysw.create_time < 1647446400 AND ysw.apply_status IN (10,20,40) GROUP BY ysw.supply_id
ORDER BY SUM(ysw.money) DESC ) AS t1 
	
 LEFT JOIN

    (SELECT  supply_id  AS &#39;supply_id&#39; , COUNT(order_id) AS order_id,   SUM(total_pay_price)    AS total_pay_price 
    FROM 	yoshop_order_goods WHERE  create_time < 1647446400 AND order_pay_status = 0  
    AND  order_id IN(
        SELECT order_id FROM yoshop_order WHERE order_status IN (10,30) 
    AND order_id NOT IN (
        SELECT order_id FROM yoshop_order_refund)	 ) 
    GROUP BY supply_id 
    ORDER BY SUM(total_pay_price) DESC ) AS t2
								
ON t1.supply_id = t2.supply_id

正确的结果截图：

MySQL派生表联表查询的示例分析

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