首页 >php教程 >PHP源码 >一个简单的用户反馈表单 (Feedback)

一个简单的用户反馈表单 (Feedback)

PHP中文网原创: 2016-05-25 17:16:032767浏览

feedback.html

<html>

 <head>
  <title>Feedback Form</title>
 </head>

 <body>

 <form action="feedback.php" method="post">
 Name:<input type="text" name="username" size="30">
 <br><br>
 Email:<input type="text" name="useraddr" size="30">
 <br><br>
 <textarea name="comments" cols="30" rows="5">
 </textarea><br>
 <input type="submit" value="Send Form">
 </form>

 </body>

</html>

feedback.php

<?php

$username = $_POST[&#39;username&#39;];
$useraddr = $_POST[&#39;useraddr&#39;];
$comments = $_POST[&#39;comments&#39;];

$to = "php@h.com";  
$re = "Website Feedback";         
$msg = $comments;            

$headers  = "MIME-Version: 1.0\r\n";  
$headers .= "Content-type: text/html; charset=iso-8859-1\r\n";
$headers .= "From: $useraddr \r\n";    
$headers .= "Cc: another@hotmail.com \r\n";

mail( $to, $re, $msg, $headers );      

?>

<html>

 <head>
  <title>Message Received</title>
 </head>

 <body>
 <h3>Thanks for your comments</h3>
 Message received from <?php echo($username); ?><br>
 Reply to <?php echo($useraddr); ?>
 </body>

</html>

声明：

本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系admin@php.cn

上一篇：PHP 的 rawurlencode() 和 rawurldecode() 函数下一篇：基于文件的网页身份认证

查看更多

一个简单的用户反馈表单 (Feedback)

feedback.html

相关文章