php如何输出json对象的值

小云云原创: 2018-03-09 10:00:111467浏览

本文主要和大家分享php如何输出json对象的值，希望能帮助到大家。

实例如下所示：

 <!DOCTYPE html>
<html>
<body>
<?php
 
$json = &#39;{"report":{"date":"2012-04-10","content":"abcdefght"}}&#39;;
 $arr = (array) json_decode($json,true);
 echo &#39;当前日期是：&#39;. $arr[&#39;report&#39;][&#39;date&#39;];
echo "<br/>";
echo &#39;<pre class="brush:php;toolbar:false">&#39;;
 print_r($arr);
echo &#39;

'; foreach($arr as $arrvalue) { foreach($arrvalue as $key=>$value) { echo "[$key] = $value
"; } } echo "
"; ?>

<!DOCTYPE html>
<html>
<body>
<?php
$file_exists = file_exists("json.txt");
if( $file_exists ){
 $myfile = fopen("json.txt", "r") or die("");
 $content = fread($myfile,filesize("json.txt"));
 fclose($myfile);
 echo $content;
 echo "<br/>";
 $arr=(array)json_decode($content,true);
 echo $arr[&#39;CSS&#39;];
 echo "<br/>";
 echo $arr[&#39;AJAX&#39;];
}
?>
 
</body>
</html>

json.txt:

{
 "AJAX": "Asynchronous JavaScript and XML",
 "CSS": "Cascading Style Sheets"
}

php如何输出json对象的值

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