python学习日记（1）
- 巴扎黑原创
- 2017-06-23 10:57:511485浏览
之前学习了Alex的python教程Alex的教学真的非常棒，也很幽默。嘿嘿。希望自己可以坚持下去。
把之前学的基础知识整理回顾了一下。希望自己可以在学习python的路上越走越远，大家互勉奥。
第一周 复习总结
1 初始游戏代码
number_of_kids =8
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
猜三次 猜三次没猜中 就退出 则要使用到循环
（ while初相识
代码1：
count = 0
while True:
print("count:",count)
count = count +1 #count +=1
无线循环-----运用到上面的猜数字游戏 ）
想要在某个地方停止 要如何设置?
简单举例while
count = 0
while True:
print("count:",count)
count = count *2 #count*=2
if count == 1000:
break
问： 该如何加？使初始游戏 能循环猜测？
改进2
number_of_kids =8
while True:
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
问题： 为什么while true 要放在这个位置？
答：while true 代表无限循环，不中断。若while true 放在下面一行的下面的话，
会无法循环下一个input，即会中断游戏。
运行结果：可无限次输入数字猜测 无限循环
缺点：当输入正确答案时仍然继续猜测，没有结束。
问：改进如何在猜对的时候 直接结束程序
改进3：
number_of_kids =8
while True:
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
break的添加可以使得在猜对数字的时候 结束游戏。但若猜不对如何是之在
指定次数内结束游戏？
改进4：
number_of_kids =8
count = 0
while True:
if count ==3:
break
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
加了 if count ==3:break 后，还是没有在第三次猜测的时候成功。
原因： 没有加计数！
number_of_kids =8
count = 0
while True:
if count ==3:
break
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
非常棒！
是否可以优化？
问：有什么可以代替 if count ==3: break 以及计数？
number_of_kids =8
count = 0
是否还可以优化？
有什么可以代替 if count ==3: break
while True:
if count <3:
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
print("you have tried too many times..fuck off")
只有在第三次还没有猜对的情况下进行fuckoff
进行以下修改：
number_of_kids =8
count = 0
while count <3:
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
if count ==3:
print("you have tried too many times..fuck off")
改进：高级一点哈哈哈哈
number_of_kids =8
count = 0
while count <3:
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
else:
print("you have tried too many times..fuck off")
小傻作业： 4/9 周日
如何变动代码，使得第三次出来的时候 只显示数字，不显示fuckoff，等第四次输入的时候，不提示大小，反而直接输出fuckoff？
首先，理清上一段代码的思路：count从0开始运行 进入while循环，但凡在小于3的范围内 只要猜对 就break。
没猜对 就出现smaller or bigger。当count+=1等于2时，即进入第三次循环，再一次猜错时
出现bigger or smaller 后 走下一个程序，即count+=1等于3，进入else运行，后面紧跟fuckoff。
作业改动思路：要使的第三次出来的时候 只显示数字 和小了大了提示，不显示fuckoff，则说明当count+=1等于3时，
不直接走fuckoff的程序，则说明fuckoff的设置不能出现在前面while count <3 的子程序中，而是应该并列程序，
当count=3时，继续出现猜数字的界面，后不管猜错猜对都fuckoff，并且结束。
number_of_kids =8
count = 0
while True:
if count <3:
guess_number =int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
if count ==3:
guess_number =int(input("guess_number_of_kids:"))
print("you have tried too many times..fuck off")
break
while优化课
如何用for来代替 while
number_of_kids =8
count = 0
while count <3: #for i in range（3）
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
else:
print("you have tried too many times..fuck off")
改成：
number_of_kids =8
count = 0
#for i in range（3）
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
else:
print("you have tried too many times..fuck off")
最基本的for循环。
for i in range(0,10,1): #1是默认值，可以不写，不写即代表1.
print("loop",i)
for i in range(0,10,2):
print("loop",i)
运行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
loop 0
loop 2
loop 4
loop 6
loop 8
>>>
for i in range(0,10,3):
print("loop",i)
运行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
loop 0
loop 3
loop 6
loop 9
>>>
再次优化猜数字游戏：猜三次就退出貌似很决绝，是不是可以根据个性化需求设置提示？
加：问还要不要玩？
number_of_kids=8
count=0
while count <3:
guess_number = int(input("guess_number_of_kids:"))
if guess_number == number_of_kids:
print("yep,you got it!")
break
elif guess_number> number_of_kids:
print("think smaller...")
else:
print("think bigger...")
count+=1
if count==3:
countine_confirm = input("do you want keeping guessing...?")
if countine_confirm !="n": 若是按下n则表示退出游戏
count =0 当按下回车键后表明还想玩，则程序继续执行。
task： 单独打出这段代码，理清思路。
新知识点： continue
for i in range(0,10):
if i<3:
print("loop",i)
else:
continue
print("hehe"..)
执行结果 ：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===
loop 0
hehe...
loop 1
hehe...
loop 2
hehe...
后来加断点？？？啥意思？
for i in range(0,10):
if i<3:
print("loop",i)
else:
continue(作用是跳出本次循环，进入下一次循环）
print("hehe"..)
问： 同样代码 却没有hehe？
新知识点：双循环
for i in range(10):
print("________",i)
for j in range(10):
print(j)
执行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===
________ 0
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