本文实例讲述了php检查字符串中是否包含7位GSM字符的方法。分享给大家供大家参考。具体分析如下:
下面的代码检查一个字符串是否包含任何7位GSM字符。它对短信平台上工作的人非常有用。
<?php function check_gsm($str) { $arr = array( "0x00", "0x01", "0x02", "0x03", "0x04", "0x05","0x06","0x07","0x08","0x09", "0x0A","0x0B","0x0C","0x0D","0x0E","0x0F","0x10","0x11","0x12","0x13", "0x14","0x15","0x16","0x17","0x18","0x19","0x1A","0x1B","0x1B0A", "0x1B14","0x1B28","0x1B29","0x1B2F","0x1B3C","0x1B3D","0x1B3E", "0x1B40","0x1B65","0x1C","0x1D","0x1E","0x1F","0x20","0x21","0x22", "0x23","0x24","0x25","0x26","0x27","0x28","0x29","0x2A","0x2B","0x2C", "0x2D","0x2E","0x2F","0x30","0x31","0x32","0x33","0x34","0x35","0x36", "0x37","0x38","0x39","0x3A","0x3B","0x3C","0x3D","0x3E","0x3F","0x40", "0x41","0x42","0x43","0x44","0x45","0x46","0x47","0x48","0x49","0x4A", "0x4B","0x4C","0x4D","0x4E","0x4F","0x50","0x51","0x52","0x53","0x54", "0x55","0x56","0x57","0x58","0x59","0x5A","0x5B","0x5C","0x5D","0x5E", "0x5F","0x60","0x61","0x62","0x63","0x64","0x65","0x66","0x67","0x68", "0x69","0x6A","0x6B","0x6C","0x6D","0x6E","0x6F","0x70","0x71","0x72", "0x73","0x74","0x75","0x76","0x77","0x78","0x79","0x7A","0x7B","0x7C", "0x7D","0x7E","0x7F"); $strl = strlen($str); for ($i = 0;$i < $strl; $i++) { $char = '0x' . bin2hex(substr($str,$i,1)); $pos = in_array($char,$arr); if ($pos == 1) { $j++; } } if ($j < $strl) { return false; } else { return true; } } ?>
希望本文所述对大家的php程序设计有所帮助。

php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

实现方法:1、使用“sleep(延迟秒数)”语句,可延迟执行函数若干秒;2、使用“time_nanosleep(延迟秒数,延迟纳秒数)”语句,可延迟执行函数若干秒和纳秒;3、使用“time_sleep_until(time()+7)”语句。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

php字符串有下标。在PHP中,下标不仅可以应用于数组和对象,还可应用于字符串,利用字符串的下标和中括号“[]”可以访问指定索引位置的字符,并对该字符进行读写,语法“字符串名[下标值]”;字符串的下标值(索引值)只能是整数类型,起始值为0。

方法:1、用“str_replace(" ","其他字符",$str)”语句,可将nbsp符替换为其他字符;2、用“preg_replace("/(\s|\ \;||\xc2\xa0)/","其他字符",$str)”语句。

php判断有没有小数点的方法:1、使用“strpos(数字字符串,'.')”语法,如果返回小数点在字符串中第一次出现的位置,则有小数点;2、使用“strrpos(数字字符串,'.')”语句,如果返回小数点在字符串中最后一次出现的位置,则有。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。


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