SGU

WBOY
WBOY原创
2016-06-24 11:52:291211浏览

SGU - 105

Div 3

Time Limit: 250MS   Memory Limit: 4096KB   64bit IO Format: %I64d & %I64u

Submit Status

Description

There is sequence 1, 12, 123, 1234, ..., 12345678910, ... . Given first N elements of that sequence. You must determine amount of numbers in it that are divisible by 3.

Input

Input contains N (1

Output

Write answer to the output.

Sample Input

Sample Output

Source




数学题!找规律!


规律:0,1,1,0,1,1,0,1,1,0,1,1....      (0代表不能被3整除,1代表能被3整除!)


AC代码:


#include <cstdio>#include <cstring>#include <algorithm>#include <iostream>#include <cmath>using namespace std;int main(){	int n;	scanf("%d", &n);	int ans = 0;	ans += (n/3)*2;	if(n%3==2) ans++;	printf("%d\n", ans);	return 0;} </cmath></iostream></algorithm></cstring></cstdio>






声明:
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn