首页 >后端开发 >php教程 >php json转数组出错求助

php json转数组出错求助

WBOY
WBOY原创
2016-06-23 14:23:251449浏览

1:先输出json

//组合医生信息JSON$jsonDoctorInfo  = "{\"mecdoctor\":[";$jsonDoctorInfo .= "{\"doctorId\":\"".$doctorId."\",\"doctorName\":\"".$strDoctorName."\", \"doctorprice\":\"".$strPrice."\",\"expertise\":\"".$strExpertise."\",\"departments\":\"".$strdepartments."\",\"doctorTitle\":\"".$strTitle."\",\"doctorPhoto\":\"".$strDoctorPhoto."\"}";$jsonDoctorInfo .= "]}";

2:获取并decode
$jsonGetDoctorInfoData = json_encode($jsonGetDoctorInfoData);
$objGetDoctorInfoData  = json_decode($jsonGetDoctorInfoData);
输出:
{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}

3:将json转换成数组
//解析JSON数据	function _json_decode($json){		$comment = false;		$out = '$x=';		for ($i=0; $i<strlen($json);$i++){			if (!$comment){				if ( ($json[$i] == '{') || ($json[$i] == '[') )					$out .= ' array(';				else if (($json[$i] == '}') || ($json[$i] == ']'))					$out .= ')';				else if ($json[$i] == ':')					$out .= '=>';				else					$out .= $json[$i];          			}else				$out .= $json[$i];			if($json[$i]== '"' && $json[($i-1)]!="\\")				$comment = !$comment;		}		eval($out.";");				return $x;	}

4:出现问题
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()'d code on line 1



回复讨论(解决方案)

请帮我看看到底是错到哪了。

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s, true));
Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))
你并没有给出出错行附近的代码,自然也就不知道你遇到了什么问题了

谢谢版主,
我在第二步获取JSON后,将$s带入function _json_decode($json){中出现错误
4:出现问题
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()'d code on line 1



$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s, true));
Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))
你并没有给出出错行附近的代码,自然也就不知道你遇到了什么问题了

另外请问一下,为什么我通过file_get_content获取的JSON字串,decode的时候加了true参数就没法解析成数组,但是直接将获取的json付给一个变量后测试就能转成数组呢

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出

请问这是为什么?

没有问题呀

$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(_json_decode($s));    function _json_decode($json){        $comment = false;        $out = '$x=';        for ($i=0; $i  
Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

是啊版主,但是用file获取的就不行。
另外请问一下,为什么我通过file_get_content获取的JSON字串,decode的时候加了true参数就没法解析成数组,但是直接将获取的json付给一个变量后测试就能转成数组呢

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出

请问这是为什么?

$urlGetDoctorInfo = "http://127.0.0.1:8080/mobileInterface/mobileDataInterface.php?Action=showDoctorInfo&doctorid=".$_REQUEST['doctorid'];$jsonGetDoctorInfoData =  file_get_contents($urlGetDoctorInfo);print_r(json_decode($jsonGetDoctorInfoData ,true));//数据就是空的//将字串穿付给变量后$s= '{"mecdoctor":[{"doctorId":"","doctorName":"XXX", "doctorprice":"122","expertise":"XXX","departments":"内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(json_decode($s,true));//正常输出版主大人,麻烦你看看这是什么问题呢,刚那个问题好了。

没有问题呀
$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';print_r(_json_decode($s));    function _json_decode($json){        $comment = false;        $out = '$x=';        for ($i=0; $i  
Array(    [mecdoctor] => Array        (            [0] => Array                (                    [doctorId] =>                     [doctorName] => XXXX                    [doctorprice] => 122                    [expertise] => XXXXX                    [departments] => 医内科                    [doctorTitle] => 主任医师                    [doctorPhoto] => hmh                )        ))

那是编码问题!
json_decode 只能识别 utf-8 编码的数据

声明:
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn