请问一下该如何解析出这个数组呢？谢谢了。
- WBOY原创
- 2016-06-23 14:23:13841浏览
Array( [doctorDate] => Array ( [0] => Array ( [doctorOfDate] => 2013-10-02 [orderingCount] => 12 ) [1] => Array ( [doctorOfDate] => 2013-10-03 [orderingCount] => 8 ) ) )
回复讨论(解决方案)
什么意思？你想做什么
假设数组名为:test
test['doctorDate'][0]['doctorOfDate']=2013-10-02
test['doctorDate'][0]['orderingCount']=12
test['doctorDate'][1]['doctorOfDate']=2013-10-03
test['doctorDate'][1]['orderingCount']=8
这个数组的定义是：
test=array('doctorDate'=> array(0=>array('doctorDate'=>'2013-10-02', 'orderingCount'=>12), 1=>array('doctorDate'=>'2013-10-03', 'orderingCount'=>8) ) ) 我就想把这个数组的数据显示成：
2013-10-02 12
2013-10-02 8
我就想把这个数组的数据显示成：
2013-10-02 12
2013-10-02 8
Array( [doctorDate] => Array ( [0] => Array ( [doctorOfDate] => 2013-10-02 [orderingCount] => 12 ) [1] => Array ( [doctorOfDate] => 2013-10-03 [orderingCount] => 8 ) ) )
<?php$test=array('doctorDate'=> array(0=>array('doctorDate'=>'2013-10-02', 'orderingCount'=>12), 1=>array('doctorDate'=>'2013-10-03', 'orderingCount'=>8) ) );foreach ($test as $arr){foreach ($arr as $value){echo $value['doctorDate'].' '.$value['orderingCount'].'<br>';}}?> 声明：
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