数组文件操作

本帖最后由 lazygc520 于 2013-09-05 13:13:44 编辑

已知数组a和数组b

$a = array ( 0 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2X15',    'count' => '0',  ),  1 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2Z15',    'count' => '16',  ),);$b = array (  0 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2X15',    'count' => '0',  ),  1 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2Z15',    'count' => '32',  ),  2 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '3528',    'count' => '80',  ),);

想要得到的结果是当数组b和数组a的cust_no和lotno都相同时，则提示update table sql
否则insert table sql。请问怎么求？

回复讨论(解决方案)

你这是二维啊，谁跟谁相同？

你这是二维啊，谁跟谁相同？
我用foreach来遍历2个2维数组，就例中而言，数组b存在： 'cust_no' => '310F6 1VA5A', 'lotno' => '2X15'
数组a也存在： 'cust_no' => '310F6 1VA5A', 'lotno' => '2X15'。因为对应的cust_no和lotno键值都相等，所以进行update操作。

foreach ($a as $a1) {
    foreach ($b as $b1) {
        if $a1['cust_no'] == $b1['cust_no'] && $a1['lotno'] == $b1['lotno'] {
        ...

你都四角了，我感觉你这帖子是在开玩笑吧？

$a = array ( 0 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2X15',    'count' => '0',  ),  1 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2Z15',    'count' => '16',  ),); $b = array (  0 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2X15',    'count' => '0',  ),  1 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '2Z15',    'count' => '32',  ),  2 =>   array (    'cust_no' => '310F6 1VA5A',    'lotno' => '3528',    'count' => '80',  ),);foreach($b as $i=>$v) {  print_r($v);  if(isset($a[$i]) && count(array_intersect_assoc($v, $a[$i])) == count($v)) {     echo "update table sql\n";  }else echo "insert table sql\n";}

Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2X15
    [count] => 0
)
update table sql
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2Z15
    [count] => 32
)
insert table sql
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 3528
    [count] => 80
)
insert table sql

你都四角了，我感觉你这帖子是在开玩笑吧？
可能我表述不清，结果不是这样的。

foreach($bb as $cc)			{				foreach($tt as $tts)				{					if(($tts['cust_no'] == $cc['cust_no'])&&($tts['lotno'] == $cc['lotno']))					{						$sql = "update `".$o."` set count = '".$tts['count']."' where cust_no = '".$tts['cust_no']."' and lotno = '".$tts['lotno']."'";						echo $sql.'<br />';					}					else					{						$sql2 = "insert into `".$o."`(cust_no,lotno,count) values ('".$tts['cust_no']."','".$tts['lotno']."','".$tts['count']."')";						echo $sql2.'<br />';					}				}			}//结果是这样的：update `kw_mount` set count = '0' where cust_no = '310F6 1VA5A' and lotno = '2X15'insert into `kw_mount`(cust_no,lotno,count) values ('310F6 1VA5A','2Z15','32')insert into `kw_mount`(cust_no,lotno,count) values ('310F6 1VA5A','3528','80')insert into `kw_mount`(cust_no,lotno,count) values ('310F6 1VA5A','2X15','0')update `kw_mount` set count = '32' where cust_no = '310F6 1VA5A' and lotno = '2Z15'insert into `kw_mount`(cust_no,lotno,count) values ('310F6 1VA5A','3528','80')//而我想得到的结果是update `kw_mount` set count = '0' where cust_no = '310F6 1VA5A' and lotno = '2X15'update `kw_mount` set count = '32' where cust_no = '310F6 1VA5A' and lotno = '2Z15'insert into `kw_mount`(cust_no,lotno,count) values ('310F6 1VA5A','3528','80')

这样要怎么求？

Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2X15
    [count] => 0
)
update table sql
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2Z15
    [count] => 32
)
insert table sql 
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 3528
    [count] => 80
)
insert table sql
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2X15
    [count] => 0
)
update table sql
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 2Z15
    [count] => 32
)
insert table sql //这里要变成update table sql，因为cust_no和lotno都相同
Array
(
    [cust_no] => 310F6 1VA5A
    [lotno] => 3528
    [count] => 80
)
insert table sql

要什么条件自己改

foreach($b as $i=>$v) {  print_r($v);  if(isset($a[$i]) && $v['cust_no'] == $a[$i]['cust_no'] && $v['lotno'] == $a[$i]['lotno']) {     echo "update table sql\n";  }else echo "insert table sql\n";}