首页 >后端开发 >php教程 >这样写的sql哪里有问题呢

这样写的sql哪里有问题呢

WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB
WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB原创
2016-06-23 13:41:27758浏览

SQL句是没有问题的,测试了,能输出数据来,
但就是报错,不知哪里有问题

<?php $con=mysql_connect('localhost','root','root');//数据库信息mysql_select_db("phpcmsutf8test",$con);//数据库名mysql_query("set names utf8");//设置字符集编码$catidd=$_GET['catid'];echo $catidd;$sql = mysql_query("SELECT jh_comment.title, jh_comment.total, jh_comment.square FROM jh_comment INNER JOIN jh_video ON jh_comment.title = jh_video.title WHERE jh_video.catid = $catidd");$arr = array();while($row = mysql_fetch_assoc($sql,$con)){		$arr[]= $row;	}if($arr[0]['total']!=0){	$comtotal=$arr[0]['total']; 	$comsqu=$arr[0]['square']; 	$hlu=($comsqu/$comtotal)*100;	$hlu=sprintf("%.1f",$hlu).'%';			echo "\$('.comment_lu').html('$hlu');";/	echo "\$('#comment_total').html('$comtotal');";?> 

报错见下图


回复讨论(解决方案)

参数多了!
while($row = mysql_fetch_assoc($sql)){

声明:
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn