见鬼,为什么这个内置函数这样写不行?
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ -->$path = 'E:/Zl/资料-1/资料库/3005 奥迪A6L新型C6原厂资料'; function get_filetree($path){ $tree = array(); foreach(glob($path."/{*.pdf,*.doc,*.ppt}", GLOB_BRACE) as $single){ if(is_dir($single)){ $tree = array_merge($tree,get_filetree($single)); } else{ $tree[] = $single; } } return $tree; } print_r(get_filetree($path));
function get_filetree($path){ $tree = array(); foreach(glob($path."/*.{pdf,doc,ppt}", GLOB_BRACE) as $single) { if(is_file($single)) $tree[] = $single; } foreach(glob($path."/*", GLOB_ONLYDIR ) as $single) { $tree = array_merge($tree,get_filetree($single)); } return $tree; } <br><font color="#e78608">------解决方案--------------------</font><br> 你#6的写法也是可以的,但用错了目标<br>if(glob($path."*/*.{pdf,doc,ppt}", GLOB_BRACE)){<br>应为<br>if(glob($single."{pdf,doc,ppt}", GLOB_BRACE)){<br>目的是判断 $single 的后缀是否符合要求<br><br>我#4的代码:<br> //取得所有符合条件的文件名<br> foreach(glob($path."/*.{pdf,doc,ppt}", GLOB_BRACE) as $single) {<br> if(is_file($single)) $tree[] = $single;<br> }<br> //遍历所有子目录<br> foreach(glob($path."/*", GLOB_ONLYDIR ) as $single) {<br> $tree = array_merge($tree,get_filetree($single));<br> }<br> <div class="clear"> </div>