preg_replace 替换的有关问题

preg_replace 替换的问题

PHP code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->    $string =         <img  src="/static/imghwm/default1.png" data-src="/img/pvistely/2.jpg" class="lazy" alt="preg_replace 替换的有关问题" >        <img  src="/static/imghwm/default1.png" data-src="/img/pvistely/3.jpg" class="lazy" alt="preg_replace 替换的有关问题" >        ……………………str;    $pattern = array('<img  src="/static/imghwm/default1.png" data-src="/img/pvistely/1.jpg" class="lazy" alt="preg_replace 替换的有关问题" >','<img  src="/static/imghwm/default1.png" data-src="/img/pvistely/2.jpg" class="lazy" alt="preg_replace 替换的有关问题" >','<img  src="/static/imghwm/default1.png" data-src="/img/pvistely/3.jpg" class="lazy" alt="preg_replace 替换的有关问题" >');    $replace = array('[img]1.jpg[/img]','[img]2.jpg[/img]','[img]3.jpg[/img]');    echo preg_replace($pattern, $replace, $string);

得到这样的结果：

PHP code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->    ……………………                    ……………………

为什么会多出两个尖括号 ?
要怎么才能把这个 也替换掉？

------解决方案--------------------
$pattern = array('>','>','>');
------解决方案--------------------
你用的是 preg_replace
$pattern 项中两端的被当做规则串的分界符了

用 str_replace 就可以了