如何使用 PHP 从 MySQL 数据库动态生成 HTML 表？

使用 MySQL 和 PHP 动态创建 HTML 表

尽管有描述如何使用 PHP 和 MySQL 在 HTML 中构建表的帖子，但之后频繁更改 MySQL 列标题创建表可能会很麻烦。本文探讨了一种自动更新 PHP 代码的方法，允许您指定表名称并打印该表，而无需手动插入

。

$table = "user";
$database = "database";
$conn = mysqli_connect("localhost", "username", "password", "database", "3306");

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT * FROM $table";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
        echo "<tr>
<td>" . $row["id"] . "</td>
<td>" . $row["first_name"] . "</td>
<td>" . $row["last_name"] . "</td>
<td>" . $row["birthday"] . "</td>
</tr>";
    }
    echo "";
} else {
    echo "0 result";
}

$conn->close();

动态解决方案

为了简化流程，可以创建一个函数来动态执行这些操作。它检查表是否存在，获取数据，并生成带标题的 HTML 表。

MySQLi 解决方案

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = mysqli_connect("localhost", "username", "password", "database", "3306");
$mysqli->set_charset('utf8mb4'); // always set the charset

function outputMySQLToHTMLTable(mysqli $mysqli, string $table)
{
    // Verify table existence
    $tableNames = array_column($mysqli->query('SHOW TABLES')->fetch_all(), 0);
    if (!in_array($table, $tableNames, true)) {
        throw new UnexpectedValueException('Unknown table name provided!');
    }

    $res = $mysqli->query('SELECT * FROM ' . $table);
    $data = $res->fetch_all(MYSQLI_ASSOC);

    echo '

'; // Table header echo ''; echo ''; foreach ($res->fetch_fields() as $column) { echo ''; } echo ''; echo ''; // Table body if ($data) { foreach ($data as $row) { echo ''; foreach ($row as $cell) { echo ''; } } else { echo ''; } echo '

name) . '

'; } echo '

No records in the table!

'; } outputMySQLToHTMLTable($mysqli, 'user');

PDO 解决方案

$pdo = new PDO("mysql:host=localhost;dbname=test;charset=utf8mb4", 'username', 'password', [
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_EMULATE_PREPARES => false
]);

function outputMySQLToHTMLTable(pdo $pdo, string $table)
{
    // Verify table existence
    $tableNames = $pdo->query('SHOW TABLES')->fetchAll(PDO::FETCH_COLUMN);
    if (!in_array($table, $tableNames, true)) {
        throw new UnexpectedValueException('Unknown table name provided!');
    }

    $stmt = $pdo->query('SELECT * FROM ' . $table);
    $data = $stmt->fetchAll(PDO::FETCH_ASSOC);
    $columnCount = $stmt->columnCount();

    echo '

'; // Table header echo ''; echo ''; for ($i = 0; $i getColumnMeta($i)['name']) . ''; } echo ''; echo ''; // Table body if ($data) { foreach ($data as $row) { echo ''; foreach ($row as $cell) { echo ''; } } else { echo ''; } echo '

'; } echo '

No records in the table!

'; } outputMySQLToHTMLTable($pdo, 'user');

此优化解决方案验证使用更高效的查询的表存在性：

$tableNames = $pdo->prepare('SELECT COUNT(1) FROM information_schema.TABLES WHERE TABLE_SCHEMA = SCHEMA() AND TABLE_NAME=?');
$tableNames->execute([$table]);
if (!$tableNames->fetchColumn()) {
    throw new UnexpectedValueException('Unknown table name provided!');
}

以上是如何使用 PHP 从 MySQL 数据库动态生成 HTML 表？的详细内容。更多信息请关注PHP中文网其他相关文章！