如何在 Python 中将数字单词转换为整数？

将数字单词转换为整数

通常，需要转换表示为文本的数字单词（例如，“一”、“二” ") 转化为相应的整数

解决方案：

为了促进这种转换，引入了一个名为 text2int 的 Python 函数，它利用数字词 (numwords) 的综合字典来映射文本表示为整数。这是实现：

def text2int(textnum, numwords={}):
    if not numwords:
        # Initialize the numwords dictionary only on the first call
        units = [
            "zero", "one", "two", "three", "four", "five", "six", "seven", "eight",
            "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
            "sixteen", "seventeen", "eighteen", "nineteen",
        ]

        tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]

        scales = ["hundred", "thousand", "million", "billion", "trillion"]

        numwords["and"] = (1, 0)
        for idx, word in enumerate(units):    numwords[word] = (1, idx)
        for idx, word in enumerate(tens):     numwords[word] = (1, idx * 10)
        for idx, word in enumerate(scales):   numwords[word] = (10 ** (idx * 3 or 2), 0)

    current = result = 0
    for word in textnum.split():
        if word not in numwords:
            raise Exception("Illegal word: " + word)

        scale, increment = numwords[word]
        current = current * scale + increment
        if scale > 100:
            result += current
            current = 0

    return result + current

示例：

考虑以下输入：“70亿1亿31337”

print text2int("seven billion one hundred million thirty one thousand three hundred thirty seven")  # 7100031337

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