使用 PHP 上传图像时如何将文件名和表单数据存储在数据库中？

上传图片时将文件名存入数据库

问题：

一个存储如何使用 PHP 将图像上传到服务器时，数据库中的文件名和其他表单数据？

解决方案：

1.表单结构：

使用以下 HTML 代码创建一个捕获所需信息的表单：

<code class="html"><form method="post" action="addMember.php" enctype="multipart/form-data">
  <p>Band Member Name:</p>
  <input type="text" name="nameMember">
  <p>Member's Position:</p>
  <input type="text" name="bandMember">
  <p>Photo:</p>
  <input type="hidden" name="size" value="350000">
  <input type="file" name="photo">
  <p>Other Information:</p>
  <textarea rows="10" cols="35" name="aboutMember"></textarea>
  <p>Other Bands:</p>
  <input type="text" name="otherBands" size=30>
  <input type="submit" name="upload" value="Add Member">
</form></code>

2.服务器端代码：

使用以下 PHP 脚本处理表单数据：

<code class="php">// Database connection and selection
$conn = mysqli_connect("host", "username", "password", "database");
if (!$conn) {
  die("Database connection failed: " . mysqli_connect_error());
}

// Form data extraction
$name = $_POST['nameMember'];
$bandMember = $_POST['bandMember'];
$photo = $_FILES['photo']['name'];
$about = $_POST['aboutMember'];
$bands = $_POST['otherBands'];

// Photo upload target directory
$target = "directory/";
$target .= basename($photo);

// Insert data into the database
$sql = "INSERT INTO tableName (nameMember, bandMember, photo, aboutMember, otherBands) VALUES ('$name', '$bandMember', '$photo', '$about', '$bands')";
$result = mysqli_query($conn, $sql);

// Check for successful insertion
if ($result) {
  // If successful, move the uploaded photo to the server
  if (move_uploaded_file($_FILES['photo']['tmp_name'], $target)) {
    echo "File uploaded and data saved successfully.";
  } else {
    echo "Error uploading file.";
  }
} else {
  echo "Error saving data.";
}
mysqli_close($conn);</code>

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