TypeError When Substituting Placeholder with % Formatting
When attempting to substitute a placeholder like {0} using % formatting, developers may encounter the following error: "TypeError: not all arguments converted during string formatting." This error stems from improper formatting, specifically due to a mix-up between old-style % formatting and new-style {} formatting.
Old-style % formatting employs placeholders like %d for formatting, as exemplified below:
'It will cost $%d dollars.' % 95
However, when utilizing multiple values, they must be provided as a tuple:
"'%s' is longer than '%s'" % (name1, name2)
On the other hand, new-style {} formatting employs placeholders like {} and the .format method. It's crucial to avoid mixing these two styles. If the template string contains {} placeholders, .format should be used, not %.
# Correct: 'It will cost ${0} dollars.'.format(95) "'{0}' is longer than '{1}'".format(name1, name2) # Incorrect (Do not mix % and {}): 'It will cost ${0} dollars.' % 95 "'%0' is longer than '%1'" % (name1, name2)
By adhering to these formatting guidelines, developers can resolve the "TypeError: not all arguments converted during string formatting" error and format their strings correctly.
以上是在 Python 中使用占位符格式时如何避免'类型错误:未转换所有参数”的详细内容。更多信息请关注PHP中文网其他相关文章!

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