首页 >web前端 >js教程 >js获取url中指定参数值的示例代码_javascript技巧

js获取url中指定参数值的示例代码_javascript技巧

WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB
WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB原创
2016-05-16 17:09:07933浏览

如下所示:

复制代码 代码如下:

 ///获取url中指定参数
        // 参数名称
        ///
        function request(paras) {
            var url = location.href;
            var paraString = url.substring(url.indexOf("?") + 1, url.length).split("&");
            var paraObj = {}
            for (i = 0; j = paraString[i]; i++) {
                paraObj[j.substring(0, j.indexOf("=")).toLowerCase()] = j.substring(j.indexOf("=") + 1, j.length);
            }
            var returnValue = paraObj[paras.toLowerCase()];
            if (typeof (returnValue) == "undefined") {
                return "";
            } else {
                return returnValue;
            }
        }
声明:
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系admin@php.cn