PHP实现即时网站截图[转]
- WBOY原创
- 2016-06-07 11:44:041080浏览
转一个通过PHP实现即时网站截图功能
通过一个表单来提交请求<form>
<br>
网站地址 (不带 http://):<input><br><br>
大小: <br>
<input>px<br><br>
<input>px<br><br>
图片格式:<br>
<select><br>
<option>PNG</option>
<br>
<option>JPEG</option>
<br>
</select> <br>
<br>
<input>
</form>处理页面..<?php <br />
$x = $_REQUEST['x'];<br>
$y = $_REQUEST['y'];<br>
$format = $_REQUEST['format'];<br>
$site = $_REQUEST['site'];<br>
$surl = 'http://0907.org/screenshot/screenshot_it.php?site='.$site.'&x='.$x.'&y='.$y.'&format='.$format;<br>
if($_REQUEST['format'] == 'PNG') {<br>
$ifm = 'png';<br>
} else {<br>
$ifm = 'jpg';<br>
}<br>
$imt = 'image/'.$ifm;<br>
$ifn = 'screenshot.'.$ifm;<br>
if(isset($_REQUEST['preview'])) {<br>
$iurl = 'http://域名/子目录/screenshot_it.php?site='.$site.'&x='.$x.'&y='.$y.'&format='.$format; <br>
$gwptitle = $_REQUEST['site'].' blog.0907.org';<br>
include_once("../css.php"); <br>
//这里可以删除呦！因为是CSS<br>
<br>
echo '<div>';<br>
echo '» <b>点击图片下载截图！</b>
</div>
<br><a><img alt="PHP实现即时网站截图[转]" ></a><br>';<br>
} else {<br>
header("Content-type: $imt");<br>
header("Content-Disposition: attachment; filename= $ifn");<br>
readfile($surl);<br>
}<br>
?>
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