$a[3] = 5; $a["3"] = 6; $a["3.14"] = 7; $a[3.14] = 8; echo $a[3], $a["3"], $a["3.14"], $a[3.14];
输出为什么是 8878?
回复内容:
$a[3] = 5; $a["3"] = 6; $a["3.14"] = 7; $a[3.14] = 8; echo $a[3], $a["3"], $a["3.14"], $a[3.14];
输出为什么是 8878?
http://php.net/manual/en/language.typ...
Additionally the following key casts will occur:
.....
Floats are also cast to integers, which means that the fractional part will be truncated. E.g. the key 8.7 will actually be stored under 8.
-----
in you case, the 3.14 out of $a[3.14] will be cast to 3
--------------
Strings containing valid integers will be cast to the integer type. E.g. the key "8" will actually be stored under 8.
$a[3] = 5;
$a["3"] = 6;
both are same thing and will be cast to $a[3].
----
On the other hand "08" will not be cast, as it isn't a valid decimal integer.
$a["3.14"] = 7; //"3.14" is a string and it won't be cast.
---------------
Summary:
$a[3] = 5;
$a["3"] = 6; // $a[3] is 6 now.
$a["3.14"] = 7; //"3.14" is a string, no cast then.
$a[3.14] = 8; // 3.14 will be cast to 3 which results in $a[3] = 8
echo $a[3], $a["3"], $a["3.14"], $a[3.14];
is actually
echo $a[3],$a[3],$a["3.14"],$a[3]
想起了学生时代,呵呵. 经常看这种陷阱题,其实现实中从来没遇到过.......
都用引号吧.

TheSecretTokeEpingAphp-PowerEdwebSiterUnningSmoothlyShyunderHeavyLoadInVolvOLVOLVOLDEVERSALKEYSTRATICES:1)emplactopCodeCachingWithOpcachingWithOpCacheToreCescriptexecution Time,2)使用atabasequercachingCachingCachingWithRedataBasEndataBaseLeSendataBaseLoad,3)

你应该关心DependencyInjection(DI),因为它能让你的代码更清晰、更易维护。1)DI通过解耦类,使其更模块化,2)提高了测试的便捷性和代码的灵活性,3)使用DI容器可以管理复杂的依赖关系,但要注意性能影响和循环依赖问题,4)最佳实践是依赖于抽象接口,实现松散耦合。

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选择DependencyInjection(DI)用于大型应用,ServiceLocator适合小型项目或原型。1)DI通过构造函数注入依赖,提高代码的测试性和模块化。2)ServiceLocator通过中心注册获取服务,方便但可能导致代码耦合度增加。

phpapplicationscanbeoptimizedForsPeedAndeffificeby:1)启用cacheInphp.ini,2)使用preparedStatatementSwithPdoforDatabasequesies,3)3)替换loopswitharray_filtaray_filteraray_maparray_mapfordataprocrocessing,4)conformentnginxasaseproxy,5)

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