Java类的实例化顺序
在验证《Core Java》第9版4-5代码时，发现程序输出结果和自己理解的不太一样。
import java.util.Random;
class Employee {
private static int nextId;
private int id;
private String name = "";
private double salary;
static {
Random generator = new Random();
nextId = generator.nextInt(10000);
}
{
id = nextId;
nextId++;
}
public Employee(String name, double salary) {
this.name = name;
this.salary = salary;
}
public Employee(double salary) {
this("Employee #" + nextId, salary);
}
public Employee() {
}
public String getName() {
return name;
}
public double getSalary() {
return salary;
}
public int getId() {
return id;
}
}
public class ConstructorTest {
public static void main(String[] args) {
Employee[] staff = new Employee[3];
staff[0] = new Employee("Harry", 40000);
staff[1] = new Employee(60000);
staff[2] = new Employee();
for (Employee e : staff) {
System.out.println("id = " + e.getId() + ", name = " + e.getName()
+ ", salary = " + e.getSalary());
}
}
}以下是输出结果：
id = 6943, name = Harry, salary = 40000.0
id = 6944, name = Employee #6944, salary = 60000.0
id = 6945, name = , salary = 0.0根据第一条语句得出静态初始化块生成的nextId为6943，然后在初始化块中id被赋值为6943，nextId自增后为6944。再执行第一个构造函数；
那么对于第二个对象来说，就应该直接执行初始化块，此时id为6944，nextId自增为6945。
再执行第二个构造函数，此时this("Employee #" + nextId, salary);语句中的nextId应该为6945，为什么输出结果为6944呢？
