尝试连接 119.23.124.81:7575
服务器每5秒会返回一个{"type":"ping"}
,我尝试用以下代码去连接,但是无法获取到这个{"type":"ping"}
:
s = socket(AF_INET, SOCK_STREAM)
# 建立连接:
s.connect(('119.23.124.81', 7575))
while True:
print(s.recv(1024).decode('utf-8'))
s.close()
代码不会报错,但是也获取到我想要的内容
请问要如何写才能获取到这个{"type":"ping"}
大家讲道理2017-04-18 10:27:11
搞清楚了,原來這個是使用的websocket協議,不是普通的socket
換用websocket這個函式庫就好了,程式碼如下:
from websocket import create_connection
ws = create_connection("ws://42.96.131.185:7575")
print("Sending 'Hello, World'...")
for i in range(10000):
ws.send(b"Hello, World")
print("Sent")
print("Reeiving...")
result = ws.recv()
print("Received '%s'" % result)
ws.close()
迷茫2017-04-18 10:27:11
參考官方文件
# Echo server program
import socket
HOST = '' # Symbolic name meaning all available interfaces
PORT = 50007 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()
and
import SocketServer
class MyTCPHandler(SocketServer.BaseRequestHandler):
"""
The request handler class for our server.
It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""
def handle(self):
# self.request is the TCP socket connected to the client
self.data = self.request.recv(1024).strip()
print "{} wrote:".format(self.client_address[0])
print self.data
# just send back the same data, but upper-cased
self.request.sendall(self.data.upper())
if __name__ == "__main__":
HOST, PORT = "localhost", 9999
# Create the server, binding to localhost on port 9999
server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
PHP中文网2017-04-18 10:27:11
因為你發送的資料是一個字典對象,所以在socket發送據時,用pickle或json模組對資料進行序列化再發送,對應的,接收端要用pickle或json進行反序列化操作。