我在將多個圖像檔案上傳到伺服器端時遇到問題。如果有人能夠突出顯示程式碼的問題所在,那就太好了。
最初有 HTML 程式碼:
<label class="col-form-label"><h4>Upload Images</h4></label> <div id="image-preview-container"> <!-- Preview images will be displayed here --> </div> <form id="uploadCert" enctype="multipart/form-data"> <input type="file" id="images" name="images" multiple="multiple" accept="image/*" style="display: none;"> <label for="images" class="btn btn-primary"> Add Image </label> </form> </div>
在 JavaScript 中定義
var selectedImages = []; //list of files in array
並捕獲每個選定的檔案
$("#images").change(function () { var file = this.files[0]; if (file) { ... // Append the container to the image preview container $("#image-preview-container").append(imageContainer); .. // Add the selected image file to the postData.images array selectedImages.push(file); $(this).val(""); } });
提交後使用 AJAX
$('#addcart').click(function () { // Add other form fields to formData var formData = new FormData(); ... formData.append("issuesBody", $("#fbody_").val()); ... if (selectedImages.length > 0) { // Append each selected image to formData for (var i = 0; i < selectedImages.length; i++) { var image = selectedImages[i]; if (image instanceof File) { // If it's a File object, append it to formData formData.append("images[]", image); } } } else { // If no selected images, set images[] to an empty array formData.append("images[]", []); } // Make the AJAX request event.preventDefault(); $.ajax({ url: "addcert", type: "POST", data: formData, dataType:"json", contentType:false, cache:false, processData: false, success: function(data){ // Handle a successful response ... }, error: function (xhr, status, error) { // Handle an error response ... } }); }); });
在 PHP
private function addNewCert(){ // Capture POST data $issuesBody = $this->input->post('issuesBody'); // Not sure if this is the way to capture the posted file data $images = $_FILES['images']; // Upload images to the server $uploadedFiles = $this->uploadimg($images); //Check if image uploads were successful if ($uploadedFiles === false) { // Handle the case where image uploads failed ... echo json_encode($output); return; } ...
最後在 uploadimg() 期間總是顯示 'undefined'
以及這裡的程式碼
private function uploadimg($images) { $uploadedFiles = array(); // captured uploaded file name // Loop through each uploaded file for ($i = 0; $i < count($images['name']); $i++) { // Generate a unique file name or use the original name $originalFileName = $images['name'][$i]; $fileExtension = pathinfo($originalFileName, PATHINFO_EXTENSION); $file_name = uniqid() . '_' . $originalFileName; $config['upload_path'] = $this->uploadPath; $config['file_name'] = $file_name; $config['allowed_types'] = 'jpg|jpeg|png|gif'; $config['max_size'] = 2048; $config['encrypt_name'] = TRUE; $this->load->library('upload', $config); // Perform the upload if ($this->upload->do_upload('images')) { $uploadedFiles[] = $file_name; } else { // Handle the case where an upload failed return false; } } return $uploadedFiles; }
P粉2686548732024-04-04 13:26:22
實際上,程式碼中存在不只一個問題。首先,您應該將 $this->load->library('upload',$config)
語句從 for 迴圈中取出。您需要從清單中的每個文件建立單一文件才能上傳。如果我沒有記錯的話,Codeigniter do_upload
方法不適用於多個檔案。您可以更新您的 uploadimg 方法,如下所示:
private function uploadimg($images) { $uploadedFiles = array(); // captured uploaded file name $config = [ 'upload_path' => './testUploads/', 'allowed_types' => 'jpg|jpeg|png|gif', 'max_size' => 2048, 'encrypt_name' => TRUE, ]; $this->load->library('upload', $config); // Loop through each uploaded file for ($i = 0; $i < count($images['name']); $i++) { // Generate a unique file name or use the original name $originalFileName = $images['name'][$i]; $fileExtension = pathinfo($originalFileName, PATHINFO_EXTENSION); $file_name = uniqid() . '_' . $originalFileName; $config['file_name'] = $file_name; $this->upload->initialize($config); $_FILES['singleImage']['name'] = $file_name; $_FILES['singleImage']['type'] = $images['type'][$i]; $_FILES['singleImage']['tmp_name'] = $images['tmp_name'][$i]; $_FILES['singleImage']['error'] = $images['error'][$i]; $_FILES['singleImage']['size'] = $images['size'][$i]; // Perform the upload if ($this->upload->do_upload('singleImage')) { $uploadedFiles[] = $file_name; } else { // Handle the case where an upload failed return false; } } return $uploadedFiles; }
P.S 我明白了,您正在產生一個更易讀的檔案名稱。如果您想要尋找具有該命名結構的文件,則應將配置數組中的 encrypt_name 欄位設為 false。