改變顏色取決於日期的值

Question

我想根據日期的持續時間更改整行的顏色。 例如，如果日期的持續時間在 3 到 6 之間，則顏色為橘色；超過6個必須顯示為紅色。我可以知道我該怎麼做嗎？

foreach ($ary_list as $k => $v) {

 $color= xxx;
 echo "<tr style=\"color:$color\">";
 echo  "<tr bgcolor=\"#F5F5F5\">\n";
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["seal_area"]. " &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>\n";

  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["seal_barcode"]. " &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>\n";
  
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["dt_issue"]. " &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";  
  
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["issue_admin"]. " &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";
  
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["receive_by"]." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";

  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["receive_id"]." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";
 
  
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["dt_return"]." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";

  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["return_admin"]." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";

  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["return_by"]. " &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";
  
  echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  echo  "&nbsp " .$v["return_id"]." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";
  
  /*echo "<td nowrap ".$rowspan.">\n";
  echo  "<font face=\"arial\" size=\"1\" color=\"#3C5F84\">\n";
  $now = time(); // or your date as well
    $your_date = strtotime($v["dt_issue"]);
    $datediff = $now - $your_date;

//echo round($datediff / (60 * 60 * 24));
    //echo $datediff->format('%R%a days');
  echo  "&nbsp " .round($datediff / (60 * 60 * 24))." &nbsp &nbsp ";
  echo  "</font>\n";
  echo  "</td>";*/
  
  echo "<td nowrap ".$rowspan.">\n";
    $now = time();
    $your_date = strtotime($v["dt_issue"]);
    $datediff = $now - $your_date;
    $daysDiff = round($datediff / (60 * 60 * 24));
    $color = $daysDiff < 3 ? '#3C5F84' : ($daysDiff <= 6 ? 'orange' : 'red');
    echo  "<font face=\"arial\" size=\"1\" color=\"$color\">\n";
    echo  "&nbsp " .$daysDiff." &nbsp &nbsp ";
    echo  "</font>\n";
    echo  "</td>";

  echo  "</tr>";
  
}

上面的程式碼是在 php 中我如何計算週期時間選項卡的。對於 dt_issue，它在插入查詢時與 now() 一起使用。我將在下面插入螢幕截圖。

Answer 1

您可以嘗試根據daysdiff更改字體顏色

echo "\n";
$now = time();
$your_date = strtotime($v["dt_issue"]);
$datediff = $now - $your_date;
$daysDiff = round($datediff / (60 * 60 * 24));
$color = $daysDiff < 3 ? '#3C5F84' : ($daysDiff <= 6 ? 'orange' : 'red');
echo  "\n";
echo  "  " .$daysDiff."     ";
echo  "\n";
echo  "";