假設我有一個像這樣的表:
+---+---+---+---+---+ |G1 |G2 |G3 |G4 | V | +---+---+---+---+---+ | A | B | C | D | 2 | | E | F | G | H | 4 | | C | D | A | B | 2 | | E | F | G | H | 3 | | E | I | G | L | 7 | +---+---+---+---+---+
其中G1、G3是VARCHAR型,G2、G4是INT型別
如果我在G1..G4上進行簡單的GROUP BY,我會得到:
SELECT G1,G2,G3,G4,SUM(V) as V FROM Table GROUP BY G1, G2, G3, G4; +---+---+---+---+---+ |G1 |G2 |G3 |G4 | V | +---+---+---+---+---+ | A | B | C | D | 2 | | E | F | G | H | 7 | | C | D | A | B | 2 | | E | I | G | L | 7 | +---+---+---+---+---+
我想知道是否可能在反轉的值G1、G2 <-> G3、G4上進行聚合。 我想要的結果是這樣的:
+---+---+---+---+---+ +---+---+---+---+---+ |G1 |G2 |G3 |G4 | V | |G1 |G2 |G3 |G4 | V | +---+---+---+---+---+ +---+---+---+---+---+ | A | B | C | D | 4 | 或 | C | D | A | B | 4 | | E | F | G | H | 7 | | E | F | G | H | 7 | | E | I | G | L | 7 | | E | I | G | L | 7 | +---+---+---+---+---+ +---+---+---+---+---+
我嘗試取得反轉的行,但由於重複,我仍然無法在它們上進行聚合。我的測試查詢是:
SELECT DISTINCT * FROM Table t1 JOIN Table t2 on t1.G1 = t2.G3 and t1.G2=t2.G4 and t1.G3=t2.G1 and t1.G4=t2.G2 +---+---+---+---+---+---+---+---+---+---+ |G1 |G2 |G3 |G4 | V |G1 |G2 |G3 |G4 | V | +---+---+---+---+---+---+---+---+---+---+ | A | B | C | D | 2 | C | D | A | B | 2 | | C | D | A | B | 2 | A | B | C | D | 2 | +---+---+---+---+---+---+---+---+---+---+
P粉0424552502023-09-07 00:07:33
如果我理解正確,將列的順序反轉,使得 A B C D 對應 C D A B。
select case when(g1 > g3) then g3 else g1 end G1, case when(g1 > g3) then g4 else g2 end G2, case when(g1 > g3) then g1 else g3 end G3, case when(g1 > g3) then g2 else g4 end G4, sum(V) from tbl group by case when(g1 > g3) then g3 else g1 end, case when(g1 > g3) then g4 else g2 end, case when(g1 > g3) then g1 else g3 end, case when(g1 > g3) then g2 else g4 end#