MySQL中如何使用三個表進行FULL OUTER JOIN操作？

Question

考慮以下表：

<code>create table `t1` (
  `date` date,
  `value` int
);

create table `t2` (
  `date` date,
  `value` int
);

create table `t3` (
  `date` date,
  `value` int
);

insert into `t1` (`date`, `value`)
values ("2022-01-01", 1),
       ("2022-03-01", 3),
       ("2022-04-01", 4);
       
insert into `t2` (`date`, `value`)
values ("2022-01-01", 1),
       ("2022-02-01", 2),
       ("2022-04-01", 4);

insert into `t3` (`date`, `value`)
values ("2022-01-01", 1),
       ("2022-02-01", 2),
       ("2022-03-01", 3);
</code>

t1表缺少2022-02-01日期，2022-02-01日期，t2缺少2022-code>t2缺少，t3缺2022-04-01。我想要將這三個表連接起來，產生以下結果：

| t1.date | t1.value | t2.date | t2.value | t3.date | t3.value |
| | | | | | |
| 2022-01-01 | 1 | 2022-01-01 | 1 | 2022-01-01 | 1 |
| null | null | 2022-02-01 | 2 | 2022-02-01 | 2 |
| 2022-03-01 | 3 | null | null | 2022-03-01 | 3 |
| 2022-04-01 | 4 | 2022-04-01 | 4 | null | null |

我知道如何在兩個表之間進行full outer join，但是在三個或更多表之間，情況會更複雜。我嘗試了像這樣的查詢，但沒有產生我想要的結果：

<code>select *
from `t1`
left join `t2` on `t2`.`date` = `t1`.`date`
left join `t3` on `t3`.`date` = `t2`.`date` or `t3`.`date` = `t1`.`date`

union

select *
from `t1`
right join `t2` on `t2`.`date` = `t1`.`date`
right join `t3` on `t3`.`date` = `t2`.`date` or `t3`.`date` = `t1`.`date`;
</code>

Answer 1

你走在正確的軌道上，但你必須考慮所有的組合 - 3個表 - 4個聯合子句。

-- t1与t2进行全连接
select *
from `t1`
left join `t2` on `t2`.`date` = `t1`.`date` 
union 
select *
from `t1`
right join `t2` on `t2`.`date` = `t1`.`date` 

-- t1与t3进行全连接
union 
select *
from `t1`
left join `t3` on `t3`.`date` = `t1`.`date` 

union 
select *
from `t1`
right join `t3` on `t3`.`date` = `t1`.`date`