JavaScript - 從陣列中刪除重複項，並傳回一個包含重複項的陣列和另一個包含所有其他項目的陣列

Question

我想在一個數組上運行一個過濾器或縮減操作，並根據像這個例子中的'name'屬性刪除數組中的所有重複項。我看到的例子是遍歷數組並保留其中一個重複項，但在我的情況下，我需要將它們分開，並將重複項以數組的形式返回給用戶以更正數據，並處理其他剩餘項。我在下面給出了一個示例數組和期望的結果數組。如果有人能給我一個如何做到這一點的例子，我將非常感激！謝謝！

const customers = [
{ id:1, name: "John", address="123 street"},
{ id:2, name: "Alex", address="456 street"},
{ id:3, name: "John", address="674 street"},
{ id:4, name: "Stacy", address="534 street"},
{ id:5, name: "Blair", address="634 street"}
];

這將給我以下兩個陣列：

[
{ id:1, name: "John", address="123 street"},,
{ id:3, name: "John", address="674 street"},
]

和

[
{ id:2, name: "Alex", address="456 street"},
{ id:4, name: "Stacy", address="534 street"},
{ id:5, name: "Blair", address="634 street"}
]

Answer 1

嘗試一下

const customers = [
  { id: 1, name: "John", address: "123 street" },
  { id: 2, name: "Alex", address: "456 street" },
  { id: 3, name: "John", address: "674 street" },
  { id: 4, name: "Stacy", address: "534 street" },
  { id: 5, name: "Blair", address: "634 street" }
];

const nameMap = new Map();
const nonUniqueCustomers = [];
const uniqueCustomers=[];
customers.forEach(customer => {
  if (!nameMap.has(customer.name)) {
    nameMap.set(customer.name, []);
  }
  nameMap.get(customer.name).push(customer);
});

nameMap.forEach(customers => {
  if (customers.length > 1) {
    nonUniqueCustomers.push(...customers);
  }else{
uniqueCustomers.push(...customers)
  
  }
});


console.log("非唯一顾客:", nonUniqueCustomers);
console.log("唯一顾客:", uniqueCustomers);