P粉7446912052023-07-26 10:58:55
您將需要使用子查詢來實現這一點。實際上,您需要取得每個約會ID的最大記錄版本:
SELECT appointment_record_version_number, appointment_id, appointment_pallets AS close_pallets, appointment_units AS close_units FROM b.dh AS t1 WHERE t1.appointment_record_version_number = ( SELECT MAX(appointment_record_version_number) FROM b.dh WHERE b.dh.data = t1.data ) AND last_updated_datetime BETWEEN '2023-06-01' AND '2023-06-30' AND warehouse_id = 'xxx'
你也可以使用JOIN語句來選擇最大值,有時會更快:
SELECT t1.appointment_record_version_number, t1.appointment_id, t1.appointment_pallets AS close_pallets, t1.appointment_units AS close_units FROM b.dh AS t1 LEFT JOIN b.dh AS t2 ON ( t1.appointment_record_version_number = t2.appointment_record_version_number AND t1.appointment_id < t2.appointment_id ) WHERE t2.appointment_record_version_number IS NULL AND last_updated_datetime BETWEEN '2023-06-01' AND '2023-06-30' AND warehouse_id = 'xxx';
根據您的用例,特別是如果您的資料庫很大,您可以使用其他子查詢或索引來進一步優化請求,但它已經相當快了。