python如何轉換時間戳到"2017年6月12日 18點24分"這樣的格式呢？

Question

python如何轉換時間戳到"2017年6月12日 18點24分"這樣的格式呢？謝謝

import time
timestamp = time.time()
time.strftime('%Y年%m月%d日 %H时%M分', time.localtime(timestamp))
Traceback (most recent call last):
  File "<input>", line 1, in <module>
UnicodeEncodeError: 'locale' codec can't encode character '\u5e74' in position 2: Illegal byte sequence

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Answer 1

雷雷

Answer 2

還真被我研究出來種萬能方法，據我百度Google貌似這還是世上獨一份？

話不多說，下面上解決原理及方案：

官方文件：https://docs.python.org/3/lib...

---

class time.`struct_time`¶

The type of the time value sequence returned by gmtime(), localtime(), and strptime(). It is an object with a named tupleptime()

. It is an object with a named tupled 4000m. The following values are present:IndexAttributeValues0(for example, 1993)1range [1, 12]2range [1, 31]3range [0, 23]4range [0, 59]5 description6range [0, 6], Monday is 07range [1, 366]80, 1 or -1; see belowN/Aabbreviation of timezone nameN/Aoffset east of UTC in seconds

	tm_year
	tm_mon
	tm_mday
	tm_hour
	tm_min
	tm_sec	range [0, 61]; see (2) in strftime()
	tm_wday
	tm_yday
	tm_isdst
	tm_zone
	tm_gmtoff

Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].In calls to mktime(), tm_isdst y is is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.
When a tuple with an incorrect state being filled in.When a tuple with an incorrect state being filled in.When a tuple with an incorrect length is passrrect struct_time, or having elements of the wrong type, a

TypeError

---

is raised.

看文件可以得知time.localtime()回傳的元組結構，我要用到的是年月日時分，前5個，於是乎，程式碼：

import time
print('%s年%s月%s日 %s时%s分' % time.localtime(1497254119.69407)[:5])

輸出：

2017年6月12日 15时55分

搞定。

🎜轉載請註明出處，謝謝。 🎜