我的資料庫表格結構如下:
#欄位分別是ID,NUM1,NUM2, TIME1,TIME2, MONEY.
想要依照15分鐘為間隔來統計ID的數量。效果如同下面的sql語句。
SELECT
sum(CASE when TIME1 >= '2014-02-27 8:00:00' and TIME1 < '2014-02-27 8:15:00' then 1 else 0 end) AS '1',
sum(CASE when TIME1 >= '2014-02-27 8:15:00' AND TIME1 < '2014-02-27 8:30:00' then 1 else 0 end) AS '2',
sum(CASE when TIME1 >= '2014-02-27 8:30:00' AND TIME1 < '2014-02-27 8:45:00' then 1 else 0 end) AS '3',
sum(CASE when TIME1 >= '2014-02-27 8:45:00' AND TIME1 < '2014-02-27 9:00:00' then 1 else 0 end) AS '4',
sum(CASE when TIME1 >= '2014-02-27 9:00:00' and TIME1 < '2014-02-27 9:15:00' then 1 else 0 end) AS '5'
from dealdata;
#但是像上面那麼寫重複程式碼多,如果我改成30分鐘的話,就要改動很多,所以求助sql大神,看有什麼好的方法。
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謝謝 arm 同志的幫助,現在能查詢出現了
#count(id)就是進站的人
但是有的時間段,根本沒有進站的人,所以有的時間段沒有,例如5:00 -- 5:15
如果要將沒有進站的人的時段補全為0,該怎麼做呢?
我想大声告诉你2017-05-25 15:10:22
謝邀,可以縱向排列的化,如下
SELECT count(id)
from dealdata
where timestampdiff(minute,'2014-02-27 9:15:00',`TIME1`)<0 and timestampdiff(minute,'2014-02-27 8:00:00',`TIME1`)>=0
group by floor(timestampdiff(minute,'2014-02-27 8:00:00',`TIME1`)/15)
where 限制時間段,group by裡面除以你需要的時間間隔。
我不知道你為什麼出錯,可能跟mysql版本有關,我是mysql5.6
SELECT count(*),
floor(timestampdiff(minute,'2017-1-18 16:00:00',`time`)/30),
date_add('2017-1-18 16:00:00',interval 30*floor(timestampdiff(minute,'2017-1-18 16:00:00',`time`)/30) MINUTE)
FROM 我是马赛克.我是马赛克
group by floor(timestampdiff(minute,'2017-1-18 16:00:00',`time`)/30)
結果
看了下,跑的還蠻快的,0.3s不到