這個問題有點類似 Mysql 中 order by ,需要的就是在陣列中模擬不同欄位的排序。
假如有以下數組:
$beforeSort = [
"0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ],
"1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ],
"2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ],
];
現在需要在數組中按照 chinese
順序,假如有相同,就按 math
順序,最後得到的應該是如下的數組:
$afterSort = [
"2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ],
"0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ],
"1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ],
];
請問大家有什麼不同的方法可以實現?
ringa_lee2017-05-16 13:10:20
這是我自己使用的版本,使用方法:
$afterSort = getArraySort($beforeSort, 'chinese', 'SORT_ASC', 'math', 'SORT_ASC');
/**
* 二维数组排序(数字索引数组将重建索引)
* @param array $arr 需要排序的数组 二维数组
* @param string $arg1 排序的键名或字段名
* @param string $arg2 排序的顺序 SORT_ASC或SORT_DESC
* @param string $arg3 排序的方法 SORT_REGULAR
* @return array
*/
function getArraySort($arr, $arg1, $arg2 = "SORT_ASC", $arg3 = "SORT_REGULAR")
{
if (!is_array($arr) || !$arr)
{
return $arr;
}
$argcount = func_num_args();
for ($i = 1; $i < $argcount; $i++)
{
$arg = func_get_arg($i);
if (!preg_match("/SORT_(.*)/i", $arg))
{
$keynamelist[] = $arg;
$sortrule[] = '$' . $arg;
}
else
{
$sortrule[] = $arg;
}
}
foreach ($arr AS $key => $info)
{
foreach ($keynamelist AS $keyname)
{
${$keyname}[$key] = $info[$keyname];
}
}
$evalstring = 'array_multisort(' . join(",", $sortrule) . ',$arr);';
eval($evalstring);
return $arr;
}
迷茫2017-05-16 13:10:20
$beforeSort = [
"0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ],
"1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ],
"2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ],
];
$arr = array();
foreach($beforeSort as $value) {
$arr[$value['chinese']][$value['math']] = $value;
}
sort($arr);
$result = array();
foreach($arr as $val) {
sort($val);
foreach($val as $vo) {
$result[] = $vo;
}
}
var_dump($result);die;
列印結果:
array(3) {
[0]=>
array(4) {
["name"]=>
string(6) "老王"
["english"]=>
int(30)
["chinese"]=>
int(50)
["math"]=>
int(80)
}
[1]=>
array(4) {
["name"]=>
string(6) "张三"
["english"]=>
int(80)
["chinese"]=>
int(60)
["math"]=>
int(50)
}
[2]=>
array(4) {
["name"]=>
string(6) "李四"
["english"]=>
int(50)
["chinese"]=>
int(60)
["math"]=>
int(70)
}
}
PHPz2017-05-16 13:10:20
//現在需要在數組中按照 chinese 順序,假如有相同,就按 math 順序,最後得到的應該是如下的數組:
$beforeSort = [
"0" => ["name" => "张三", "english" => 80, "chinese" => 60, "math" => 50 ],
"1" => ["name" => "李四", "english" => 50, "chinese" => 60, "math" => 70 ],
"2" => ["name" => "老王", "english" => 30, "chinese" => 50, "math" => 80 ],
];
$data_math = array_column($beforeSort,'math');
$data_chinese = array_column($beforeSort,'chinese');
,$datasultisort($data_chinese,SOSO_Scfore_multisort" ort );
大家讲道理2017-05-16 13:10:20
///借用樓上哥們答案
usort($beforeSort, function ($a, $b) {
return [$a['chinese'], $b['math']] <=> [$b['chinese'], $a['math']];
});
天蓬老师2017-05-16 13:10:20
$排序前 = [
雷雷];
foreach ($beforeSort as $key => $value) {
雷雷}
array_multisort($chinese, SORT_ASC, $math, SORT_ASC, $beforeSort);
print_r($beforeSort);