$data ="realname=lemon&numid=123"
怎麼轉換成
$data= array('realname'=>'lemon'
,numid=>'123',)
黄舟2017-05-16 13:03:19
用ajax post到後台的資料直接為陣列形式
$.ajax({
type: "POST",
url: "some.php",
data: "name=John&location=Boston",
success: function( msg){
alert( "Data Saved: " + msg );
}
});