a=[1,2,3,4,5,6]
b=['a','b','c','d','e']
实现合并后[1,'a',2,'b',3,'c'......]这种类型
回复内容:
<span class="kn">from</span> <span class="nn">compiler.ast</span> <span class="kn">import</span> <span class="n">flatten</span>
<span class="n">a</span> <span class="o">=</span> <span class="p">[</span><span class="mi">1</span><span class="p">,</span> <span class="mi">2</span><span class="p">,</span> <span class="mi">3</span><span class="p">,</span> <span class="mi">4</span><span class="p">,</span> <span class="mi">5</span><span class="p">,</span> <span class="mi">6</span><span class="p">]</span>
<span class="n">b</span> <span class="o">=</span> <span class="p">[</span><span class="s">'a'</span><span class="p">,</span> <span class="s">'b'</span><span class="p">,</span> <span class="s">'c'</span><span class="p">,</span> <span class="s">'d'</span><span class="p">,</span> <span class="s">'e'</span><span class="p">]</span>
<span class="n">c</span> <span class="o">=</span> <span class="n">flatten</span><span class="p">(</span><span class="nb">zip</span><span class="p">(</span><span class="n">a</span><span class="p">,</span> <span class="n">b</span><span class="p">))</span>
<span class="k">print</span> <span class="n">c</span>
<span class="p">[</span><span class="mi">1</span><span class="p">,</span> <span class="s">'a'</span><span class="p">,</span> <span class="mi">2</span><span class="p">,</span> <span class="s">'b'</span><span class="p">,</span> <span class="mi">3</span><span class="p">,</span> <span class="s">'c'</span><span class="p">,</span> <span class="mi">4</span><span class="p">,</span> <span class="s">'d'</span><span class="p">,</span> <span class="mi">5</span><span class="p">,</span> <span class="s">'e'</span><span class="p">]</span>
<span class="kn">import</span> <span class="nn">itertools</span>
<span class="nb">list</span><span class="p">(</span><span class="n">itertools</span><span class="o">.</span><span class="n">chain</span><span class="o">.</span><span class="n">from_iterable</span><span class="p">(</span><span class="nb">zip</span><span class="p">(</span><span class="n">a</span><span class="p">,</span><span class="n">b</span><span class="p">)))</span>
办法有多种,其中一种,解题思路是模拟队列,由黄哥所写。

<span class="n">a</span> <span class="o">=</span> <span class="p">[</span><span class="mi">1</span><span class="p">,</span> <span class="mi">2</span><span class="p">,</span> <span class="mi">3</span><span class="p">,</span> <span class="mi">4</span><span class="p">,</span> <span class="mi">5</span><span class="p">,</span> <span class="mi">6</span><span class="p">]</span>
<span class="n">b</span> <span class="o">=</span> <span class="p">[</span><span class="s">'a'</span><span class="p">,</span> <span class="s">'b'</span><span class="p">,</span> <span class="s">'c'</span><span class="p">,</span> <span class="s">'d'</span><span class="p">,</span> <span class="s">'e'</span><span class="p">]</span>
<span class="n">c</span> <span class="o">=</span> <span class="p">[]</span>
<span class="nb">map</span><span class="p">(</span><span class="k">lambda</span> <span class="n">x</span><span class="p">,</span> <span class="n">y</span><span class="p">:</span> <span class="n">c</span><span class="o">.</span><span class="n">extend</span><span class="p">([</span><span class="n">x</span><span class="p">,</span><span class="n">y</span><span class="p">])</span> <span class="k">if</span> <span class="bp">None</span> <span class="ow">not</span> <span class="ow">in</span> <span class="p">[</span><span class="n">x</span><span class="p">,</span><span class="n">y</span><span class="p">]</span> <span class="k">else</span> <span class="bp">None</span><span class="p">,</span> <span class="n">a</span><span class="p">,</span> <span class="n">b</span><span class="p">)</span>
<span class="k">print</span> <span class="n">c</span>
<span class="p">[</span><span class="mi">1</span><span class="p">,</span> <span class="s">'a'</span><span class="p">,</span> <span class="mi">2</span><span class="p">,</span> <span class="s">'b'</span><span class="p">,</span> <span class="mi">3</span><span class="p">,</span> <span class="s">'c'</span><span class="p">,</span> <span class="mi">4</span><span class="p">,</span> <span class="s">'d'</span><span class="p">,</span> <span class="mi">5</span><span class="p">,</span> <span class="s">'e'</span><span class="p">]</span>
有规律的交叉合并可以通过for循环来实现的吧

numpyArraysareAreBetterFornumericalialoperations andmulti-demensionaldata,而learthearrayModuleSutableforbasic,內存效率段

numpyArraySareAreBetterForHeAvyNumericalComputing,而lelethearRayModulesiutable-usemoblemory-connerage-inderabledsswithSimpleDatateTypes.1)NumpyArsofferVerverVerverVerverVersAtility andPerformanceForlargedForlargedAtatasetSetsAtsAndAtasEndCompleXoper.2)

ctypesallowscreatingingangandmanipulatingc-stylarraysinpython.1)usectypestoInterfacewithClibrariesForperfermance.2)createc-stylec-stylec-stylarraysfornumericalcomputations.3)passarraystocfunctions foreforfunctionsforeffortions.however.however,However,HoweverofiousofmemoryManageManiverage,Pressiveo,Pressivero

Inpython,一個“列表” isaversatile,mutableSequencethatCanholdMixedDatateTypes,而“陣列” isamorememory-sepersequeSequeSequeSequeSequeRingequiringElements.1)列表

pythonlistsandArraysareBothable.1)列表Sareflexibleandsupportereceneousdatabutarelessmory-Memory-Empefficity.2)ArraysareMoremoremoremoreMemoremorememorememorememoremorememogeneSdatabutlesserversEversementime,defteringcorcttypecrecttypececeDepeceDyusagetoagetoavoavoiDerrors。

Python和C 各有優勢,選擇應基於項目需求。 1)Python適合快速開發和數據處理,因其簡潔語法和動態類型。 2)C 適用於高性能和系統編程,因其靜態類型和手動內存管理。

選擇Python還是C 取決於項目需求:1)如果需要快速開發、數據處理和原型設計,選擇Python;2)如果需要高性能、低延遲和接近硬件的控制,選擇C 。

通過每天投入2小時的Python學習,可以有效提升編程技能。 1.學習新知識:閱讀文檔或觀看教程。 2.實踐:編寫代碼和完成練習。 3.複習:鞏固所學內容。 4.項目實踐:應用所學於實際項目中。這樣的結構化學習計劃能幫助你係統掌握Python並實現職業目標。


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