首頁 >資料庫 >mysql教程 >mysql-Mysql数据库触发器执行不成功

mysql-Mysql数据库触发器执行不成功

PHPz
PHPz原創
2016-06-06 09:45:271988瀏覽

相关mysql视频教程推荐:《mysql教程

  • Mysql数据库中有order、orderitem和goods三张表,其中order与orderitem通过order的ID字段与orderitem的orderid字段关联;其中goods与orderitem通过goods的ID字段与orderitem的goodsid字段关联;

  • 现在想做一个触发器,当一个订单被确认的时候,该订单中所有产品的剩余数量和出售数量做相应的改变,order表isvalid字段的值有其他值变为Y的时候更新goods表中store和salecount值,请问写入下的触发器为什么不能实现目的呢,另外在脚本中提示已经创建成功怎么通过SELECT * FROM information_schema.TRIGGERS;查询不到触发器呢?

  • delimiter ||
    drop trigger if exists updatestore||
    create trigger updatestore after update on order for each row
    begin
     declare numorder int(11);
     set numorder = (select count(count) from orderitem where orderid = old.id);
     if new.isvalid ='Y' and old.isvalid !='Y' then
      update goods set store = store - @numorder, salecount = salecount + @numorder where id in (select goodsid from zsorderitem where orderid = old.id);
     end if;
     if new.isvalid !='Y' and old.isvalid ='Y' then
      update goods set store = store + @numorder, salecount = salecount - @numorder where id in (select goodsid from orderitem where orderid = old.id);
     end if;
    end||
陳述:
本文內容由網友自願投稿,版權歸原作者所有。本站不承擔相應的法律責任。如發現涉嫌抄襲或侵權的內容,請聯絡admin@php.cn