首頁  >  文章  >  在 if 語句上列印成功金額語句

在 if 語句上列印成功金額語句

PHPz
PHPz轉載
2024-02-06 10:39:07981瀏覽
問題內容

我用java製作了一個atm程式。總的來說,它有效。但是,當用戶輸入成功的儲蓄和支票金額時,我試圖讓它列印「您超出了限制」。我使用 if 語句來做到這一點。但是,我不確定它是否可以產生“您超出了限制”列印。我剛開始學習 java,所以請耐心等待。

package atm;

import java.util.Scanner;

public class atm {

    public static void main(String[] args) {
        
        Scanner cin = new Scanner(System.in);
        
        int checking = 1000, savings = 5000, withdrawal = 0, deposit = 0;
        
        System.out.println("======================");
        
        System.out.println("Welcome to Sound Bank!");
        
        System.out.println("======================");
        
        while (true) {
        
        System.out.println("Please select which options: \n (C)Checking Balance \n (S)Savings");
        
        String choice1 = cin.nextLine(); 
        
        System.out.println("Please select of the following: ");
        
        System.out.println("(D)Deposit \n (W)Withdrawal \n (B)Check Balance \n (E)Exit");
        
        String choice2 = cin.nextLine(); 
        
        
            switch(choice2.toUpperCase()) {
            
            case "D":
                
                if (choice1.equalsIgnoreCase("C")) {
                    System.out.println("Enter your deposit amount:");
                    double num = cin.nextDouble();
                    double total = checking + num;
                    System.out.println("You entered" + num);
                    System.out.println("You have" + total);
                        if(num > checking) {
                            System.out.println("You are over the limit.");
                        }
                } else if (choice1.equalsIgnoreCase("S")) {
                    System.out.println("Enter your deposit amount");
                    double num1 = cin.nextDouble();
                    double total1 = savings + num1;
                    System.out.println("You entered" + num1);
                    System.out.println("You have" + total1);
                        if(num1 > savings) {
                            System.out.println("You are over the limit.");
                        }
                } 
                break;
            case "W":
                if (choice1.equalsIgnoreCase("C")) {
                    System.out.println("Enter your withdrawal amount:");
                    double w = cin.nextDouble();
                    double total2 = checking - w;
                    System.out.println("You entered" + w);
                    System.out.println("You have" + total2);
                        if(w > checking) {
                            System.out.println("You are over the limit.");
                        }
                } else if (choice1.equalsIgnoreCase("S")) {
                    System.out.println("Enter your withdrawal amount:");
                    double w2 = cin.nextDouble();
                    double total3 = cin.nextDouble();
                    System.out.println("You entered " + w2);
                    System.out.println("You have" + total3);
                        if(w2 > savings) {
                            System.out.println("You are over the limit.");
                        }
                } 
                break;
            case "B": 
                if (choice1.equalsIgnoreCase("C")) {
                    double t1 = (checking + deposit) - withdrawal;
                    System.out.println("Your total amount is:" + t1);
                } else if (choice1.equalsIgnoreCase("S")) {
                    double t2 = (savings + deposit) - withdrawal;
                    System.out.println("Your total amount is:" + t2);
                }
                break;
            case "E": 
                System.exit(0);
                break;
            }
        
    
        }

    }

}

正確答案


問題不是很清楚。但我假設你的問題已經解決了

double w2 = cin.nextDouble();

double Total3 = cin.nextDouble();

替換為

double w2 = cin.nextDouble();

double Total3 = 節省 - w2;

#它應該按預期工作。

以上是在 if 語句上列印成功金額語句的詳細內容。更多資訊請關注PHP中文網其他相關文章!

陳述:
本文轉載於:stackoverflow.com。如有侵權,請聯絡admin@php.cn刪除