在C語言中編寫一個程序，用於檢查給定的年份是否為閏年

閏年有366天，而普通年有365天，任務是透過程式檢查給定的年份是否為閏年。

判斷的邏輯可以透過檢查年份是否能被400或4整除來實現，但如果不能被這兩個數整除，則為普通年。

範例

Input-: year=2000
Output-: 2000 is a Leap Year

Input-: year=101
Output-: 101 is not a Leap year

演算法

Start
Step 1 -> declare function bool to check if year if a leap year or not
bool check(int year)
   IF year % 400 = 0 || year%4 = 0
      return true
   End
   Else
      return false
   End
Step 2 -> In main()
   Declare variable as int year = 2000
   Set check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year)
   Set year = 10
   Set check(year)? printf("%d is a Leap Year",year): printf("</p><p>%d is not a Leap Year",year);
Stop

Example

#

#include <stdio.h>
#include <stdbool.h>
//bool to check if year if a leap year or not
bool check(int year){
   // If a year is multiple of 400 or multiple of 4 then it is a leap year
   if (year % 400 == 0 || year%4 == 0)
      return true;
   else
      return false;
}
int main(){
   int year = 2000;
   check(year)? printf("%d is a Leap Year",year): printf("%d is not a Leap Year",year);
   year = 101;
   check(year)? printf("%d is a Leap Year",year): printf("</p><p>%d is not a Leap Year",year);
   return 0;
}

輸出

2000 is a Leap Year
101 is not a Leap Year

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