檢查給定字串是否是關鍵字的C程式？

關鍵字是在C 庫中預先定義或保留的單字，具有固定的含義，並用於執行內部操作。 C 語言支援超過64個關鍵字。

每個關鍵字都以小寫字母形式存在，如auto、break、case、const、continue、int等。

C 語言中的32個關鍵字也可在C語言中使用。

##for#signedvoiddefault#gotosizeofvolatile#doifstaticwhile

auto	double	int	struct
break	else	long	switch
#case	enum	register	typedef
char	extern	return	union
const	float	short	unsigned
continue

這是C 中新增的30個保留字，不在C語言中。

asmdynamic_castnamespacereinterpret_cast#boolexplicitnewstatic_castcatch#false operatortemplateclass#friendprivateconst_castdeletetry##typenameusing usingusingwchar_t

		##this
inline	public	#throw
#mutable	protected	true
typeid

##

Input: str=”for”
Output: for is a keyword

• Explanation

• #關鍵字是程式中無法用作變數名稱的保留字。

C程式語言中有32個關鍵字。

將字串與每個關鍵字進行比較，如果字串相同，則字串是關鍵字。

Example

 範例

#include <stdio.h>
#include <string.h>
int main() {
   char keyword[32][10]={
      "auto","double","int","struct","break","else","long",
      "switch","case","enum","register","typedef","char",
      "extern","return","union","const","float","short",
      "unsigned","continue","for","signed","void","default",
      "goto","sizeof","voltile","do","if","static","while"
   } ;
   char str[]="which";
   int flag=0,i;
   for(i = 0; i < 32; i++) {
      if(strcmp(str,keyword[i])==0) {
         flag=1;
      }
   }
   if(flag==1)
      printf("%s is a keyword",str);
   else
      printf("%s is not a keyword",str);
}

###輸出###

which is a keyword

###

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